Exam (elaborations)
Tecnología de Alta Frecuencia
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Examen de Tecnología de Alta Frecuencia
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DEPARTAMENTO DE TEORIA DE LASEÑAL Y COMUNICACIONES
TECNOLOGÍA DE ALTA FRECUENCIA
Final Teoría (4 p.) Junio 2017
APELLIDOS:
NOMBRE: DNI:
T-1 (1.25p). Tenemos el circuito de la figura:
0,1 3 Z1=50ohm
1 ቀ ቁ 2
0 0,2 Z1
Z0=50 ohm
a) Calcule los parámetros “S11 y S22” del conjunto formado por los dos cuadripolos
Llamando al dispositivo de la derecha a y al de la izquierda b, el dispositivo a es unilateral por lo que:
𝑇 𝑎
𝑆11 = 𝑆11 = 0,1
Para calcular ST22 y teniendo en cuenta que el dispositivo a es unilateral:
𝑎
´𝑎 𝑎
1 + 𝑆22
𝑆22 = 𝑆22 → 𝑍𝑠𝑎 = 𝑍𝑜 𝑎 = 75 Ω
1 − 𝑆22
Por lo tanto, la impedancia vista desde la puerta 2 del conjunto será:
𝑍𝑠𝑎 ∙ 𝑍1 𝑍𝑠𝑇 − 𝑍0
𝑍𝑠𝑇 = 𝑇
= 30 Ω → 𝑆22 = = −0,25
𝑍𝑠𝑎 + 𝑍1 𝑍𝑠𝑇 + 𝑍0
b) Calcule el parámetro S12 y S21 del conjunto formado por los dos cuadripolos
Por ser a unilateral:
𝑇 𝑎
𝑆21 = 𝑆21 =0
Para calcular ST12, primero calculamos los parámetros S del dispositivo b:
𝑏 𝑏
2𝑍1
𝑆21 = 𝑆12 = = 0,66
2𝑍1 + 𝑍𝑜
𝑏 𝑏
(𝑍1 ‖𝑍0 )−𝑍0 −𝑍0
𝑆11 = 𝑆22 = = = −0,33
(𝑍1 ‖𝑍0 )−𝑍0 2𝑍1 + 𝑍𝑜
Por lo tanto, tendremos que:
𝑏 𝑎
𝑏𝑇
𝑆12 𝑆12
𝑆12 = 𝑏 𝑎
= 1,86
1 − 𝑆11 𝑆22
1
, T-2 (0.75p). Tenemos un resonador prismático de dimensiones a=22mm b=11mm,
c=41mm
a) Calcular la frecuencia de resonancia en el modo TE102
La frecuencia de resonancia con m=1, n=0 y l=2 será:
𝑐 𝑚𝜋 2 𝑛𝜋 1 𝑙𝜋 2
𝑓0 = √ቀ ቁ + ቀ ቁ + ( ) = 10 𝐺𝐻𝑧
√𝜀𝑟 𝜇𝑟 𝑎 𝑏 𝑐
b) Si rellenamos el resonador con un dieléctrico de εr=9.
Indique como variará la frecuencia de resonancia
Se reduce conforme a (1⁄ ) por lo tanto, fo = 3,33 GHz
√𝜀𝑟
Comente como variará el factor de calidad del resonado.
El factor Q disminuye por las pérdidas en el dieléctrico (tg δ ˃ 0)
Represente el campo eléctrico y magnético en el resonador para el modo
TE102.
2
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