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Tecnología de Alta Frecuencia

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DEPARTAMENTO DE INGENIERÍA AUDIOVISUAL
Y COMUNICACIONES


TECNOLOGÍA DE RADIOCOMUNICACIONES
PROBLEMAS 6 puntos
DURACIÓN: 90 minutos (con resumen) 24 de Enero de 2001
===========================================
APELLIDOS:
NOMBRE: DNI:
..............................................................................................................
PROBLEMA 1.
Queremos diseñar un amplificador de mínimo ruido. Para conseguir este objetivo la




impedancia que el transistor ha de ver a su entrada es: Zop=60-12j S.




Datos:
Z0=Z1=50S Z2=75S Z4=100S Zc=-25jS
S11=0,3 S12=0,1j
S21=2,5 S22=-0,4

,a) Diseñar la red de adaptación
de entrada según el esquema
 25 j Yop
indicado en la figura. L1, Z1

(Nota: L1$0)

Z0


Yb




L2, Z 2




Yop  Ya  Yb
Z op  60  12 j  Yop  0,016  0,0032 j
Yop  0,8  0,16 j
Z L  50  25 j  YL  0,8  0,4 j




Y ' a  0,8  0,4 j  L1  0,287  103,3º Nos situamos en la Carta de Smith en YL y

Y ' b  Y ' a  Yop  0,56 j nos movemos hacia generador hasta cortar con parte
real=0,8.
Obtenemos:




Normalizamos a 75 S y tenemos que:

Y ' b 75  0,84 j  L2  0,112  41º




2

, La otra solución que tenemos es dando una
Ya''  YL  0,8  0,4 j  L1''   / 2  180º
vuelta completa en la carta de Smith(180º),
Yb''  0,24 j
obteniendo:
Yb'' 75  0,36 j  L2  0,445  160º




L2  0,112



L1''   / 2




YL  Ya''




Ya'




L'1  0,287




3

, b) Analizar la estabilidad y calcular la MAG.
S 21 
G MAG   K  K 2  1  8,415  9,25dB
S12  

  S11 S 22  S 21 S12  0,277  115
2 2 2
1   S11  S11
K  1,65
2 S12 S 21
  1
  Incondicionalmente estable
K  1




S12  S 21   op c) Diseñar la red de adaptación de salida para la máxima
S ' 22  S 22 
1  S11   op
ganancia.




Z op  Z 0 60  12 j  50
S'  0,37  0,025 j  op    0,1  0,1 j
22
Z op  Z 0 60  12 j  50




Para conseguir máxima ganancia:

 S  S 22
'
 0,37  0,025 j
1 S
Z S  Z0  22,8  1,32 j  YS  0,0437  0,0025 j
1 S

YS
/4

Z3 Z0
YL4

Z4

L4


4

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