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Samenvatting ALLE oplossingen financiële rekenkunde $5.29   Add to cart

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Samenvatting ALLE oplossingen financiële rekenkunde

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In dit document vind je alle oplossingen van het vak financiële rekenkunde gegeven door prof. Philippe Carette. Dit onderdeel vormt samen met financiële instellingen het vak financiële markten, producten en instellingen, dat wordt gegeven aan de Ugent in de derde bachelor. Hoofdstuk 1: Enkelvo...

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  • April 18, 2021
  • 26
  • 2020/2021
  • Summary

3  reviews

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By: arthurgeorge • 2 year ago

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By: KaatjeH • 2 year ago

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By: noahvervaeke10 • 2 year ago

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Financiele rekenkunde : oefeningen
HOOFDSTUK 1 :
interestrekening
"
t.lk = 2500 ( 1,08) = 5397,31

"
I. 2 k = 600 ( 1,0575 '
= 775,17

"
1.3 K = 4000 ( 11025 ) = 5651,90


'"5
1.4 K = 371,84 ( 1,0 5) =
873,31

"
1.5 4960 = k ( 1,08 )
"
4960111,08 ) = k

er = 2297 , 44



" "
/ ( 1106 ) 715,47
'
1.6 2480 =




"
1.7 24790/11,0225 ) = 9736,82

"
1.8 1110
=
370 ( 1,03)
h
1110 = ( 1103 )
370

en 3 = n.lk ( 1,03)

en 3
= m
en 1,03

Ms 37,167 = 37 jaar 2 maand en 2. dagen

"
1.9 6042,80 =
1820 ( 1,1 )
n = en ( 6042,811820)
en 1,1


12,591 12 3
µ = =
jaar 7- maand en
dagen
"
1.10 124 =
50 ( 1,025 )

en ( 124150) = 2n
en 1,025


18 391 18 jaar 4mmol 21 d
µ =
,
=




8
l " 25011 e)
'



.

353,27 = 1-


' 's
i = ( 353,271250 ) -1

i = 4,42%


"
1.12
743,68 495 ( ste )
'




=



" "
i = ( 743,681495 ) -
1

i = 2,06 %



"
1.13 2 = 1 ( 1,05 )
en (2) = n
lint , 05


n = 14 jaar 2M 15 d

, 4h
1.14 3=1 ( 1,0175 )


en (3) =
4N
en 1,0175



n =
15 jaar 10 mnd Od .




14
1,0475 )
" 15
K = 100 ( = 191,49

"
191,49 = k ( 1,0375 )
er =
106,25

2475 t -1 k ttl
1.16
, I I I )

-97 +100



4x100 = k ( htt) →
100 = K ( ( 1ft ) -1 ) K =
10010,0309
4=(4-97) ( stil =
3233,33


Ht 100 # =
in -
#-97) ( htt )
100 =
97 ( htt )

100197 -1 = i

is 3,09%

"

3233,33 =
2475 ( 1,0309 ) snoet 9 z n?
n =
en (3233,33/2475) = 8 jaar 9M Hd
en 1,0309



4-5 K 41-5
1. 17
I I I )
-
422,02 +507,30


'
Ht 507,3 =
K ( stil →
507,3 =
Klatt ) 5-1) 4=507,3/11,037575-1
5
K =
( K -

422,02 ) ( htt ) =
2510,15


µ +507,3 -

IK = Vi -


VK -


422,02) ( stilte
5
507,3 =
422,02 ( ste )
" 5
i =
(507,3/422,02) -

1

i. =
3,75%

"' "
1.18 Kati) ter =
3k ( stil

" 20
# ( stil -30 ( wi )
"
+4=0 stel 2=(11-1) al



22 -

32 -11 =D
' "°
'
( 2) 1 i i. 4,93%
µ
D= b -


40C =
9-4=5 -
=




21,2 =
-
b ± TD 3+55/2 =
2,618
Ze


3
-

55/2 =

0/382
<1


ij

, " "
1.19 248 ( 1,06 ) = 310 ( 1,03)


]
"

] [ 310 ( 1.03)
"
en [ 248 ( 1,06) = en


en 248 t mln 1,06 = en 310 + mln 1,03


en 248 -
In 310 =
mln 1,03 -

hln 1,06


en 248 -

in 310 = n n '
7J 9M 9A
en 1,03 -
en 1,06



70000 40000 40000
1.20 41 = 40000 -
5J 1 1 '
t

42 = 40000
'
10J

stift 40000 ( ste )

-




70000
'



40000 (
in
f.
=
.
t

+ „

" ' '
7- ( stil =
4 ( stil t 4 stel 2 = ( htt )
-
722 -
42 -

4 =D

D= 16 t 4. 4.7 =
128
"'

2,2 -
b ± TD =
1,093 → i = 2 -1 =
1,81%
2h


1.21
j =
0,05

Jim)
"
e- = ( 1 trim) ) en rem) :



m m
i =
( 1 +
Jim) )
'
(1
a) Serrant = 2
tof ) =
5,06 %




b) trinest =
4 5,09%

C) maand =
12 → 5,11 %

d) degel =
365 -
5,13%


1.22 i =
0,05
' ' m

rem ) = ( 1 + i) -

1

a) nl 2) =
2,47%

j (2) = MC2) . 2 =
4,94%
b) 214 ) = 1, 23%

j (4) 4,91%
=




C) rllz ) =
0,41%

j ( 12 ) =
4,89%


1.23 i = 6,5%

a) nl 2) =
3,2%

jlz) = 6 , 4%

b) 2112) = 0,53%
6, 31 %
j ( 12 ) =

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