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Samenvatting comfort (thermisch, akoestisch, ventilatie, ergonomie, visueel) - 1ste bachelor architectuur $5.24
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  7. Comfort

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Samenvatting comfort (thermisch, akoestisch, ventilatie, ergonomie, visueel) - 1ste bachelor architectuur

2 reviews
 123 views  5 purchases
  • Course
  • Comfort
  • Institution
  • Katholieke Universiteit Leuven (KU Leuven)

In dit document vindt u een uitgebreide samenvatting van de lessen comfort (thermisch, akoestisch, ventilatie, ergonomie, visueel) voor het 1ste bachelorjaar architectuur.

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Document information

  • May 27, 2021
  • 74
  • 2020/2021
  • Summary

Subjects

  • thermisch
  • akoestisch
  • ventilatie
  • ergonomie
  • visueel
  • comfort

Written for

  • Katholieke Universiteit Leuven (KU Leuven)
  • Architectuur
  • Comfort
All documents for this subject (14)

2  reviews

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By: JMK111 • 2 year ago

Translated by Google

much info not included

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By: evelienhunin • 2 year ago

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LARA VEKEMANS KULEUVEN


BARG22

COMFORT – THERMISCH

,LARA VEKEMANS KULEUVEN


Examenvragen:

1) materialenkennis ® eigenschappen, …
2) theorie uit cursus: kort en heel correct antwoorden
3) multiple choice reeks (juist/fout) » #6
4) berekening warmteweerstand/ V waarde gevel
5) temperatuurverloop van deze gevel: tekenen in
gevel en berekenen

,LARA VEKEMANS KULEUVEN


Warmtedoorgangscoëfficiënt (U-waarde) (= vraag 4)

W
Eenheden =
m2 . K

® gaat 1-dimentionaal door een constructie, loodrecht

1
U= en q = U . (Te – Ti) (q = warmteflux)
R
« ¯
RT = totale warmteweerstand wand RSi 0,125 0,125
RS = warmteovergangsweerstand aan opp0,167
RSi = interieur RSe = exterieur
RSe 0,043 0,043

Buitenwand => RT = RSi + R + RSe
Binnenwand => RT = RSi + R + RSi

R met enkel d en λ niet gelijk aan RTotaal = enkel weerstand in wand maar
is ook transmissiezone 1m voor en na wand. In deze zone is convectie en
straling aanwezig.

RT = RSe + ∑ d / λ + ∑ R U + ∑ R A + RSi
RSe + RSi + Ra ® aflezen uit gegeven tabellen
↳ (Ra telkens delen door 2)

Voorbeeldopdracht 1:

1. kalkmortel 1cm λ i = 0,70 W/mK
2. holle beton 14cm RU = 0,11
m2K/W
3. isolatie rotswol 7,5cm λ i = 0,040
W/mK
4. matig verluchte spouw 3,5cm Ra!
5. gevel baksteen 9cm λ i = 0,90 W/mK

d1 d2 d3
RT = RSi + + RU + + Ra + + RSe
λi 1 λi 2 λi 3

0,01 0,075 0,17 0,09
= 0,125 + +0,11 + + + + 0,043 = 2,333
0,70 0,040 2 0,90

1
U= = 0,429 W/m2K
RT

, LARA VEKEMANS KULEUVEN


Warmteweerstand (Rc)

d m2 . K
Rc = in
λ W

d = dikte constructielaag (m)
λ = warmtegeleidingscoëfficiënt constructielaag (W/mK)
Rc – totaal = ∑ Rc (m2K/W) van de verschillende lagen

Voorbeeld warmteweerstanden oefeneingen:
d 0,05 m
 5 cm glaswol = = = 1,47 m2K/W
λ 0,034 W /mK

d 0,14 m
 14 cm = = = 0,35 m2K/W
λ 0,40 W /mK

Rtotaal = RSe + ∑ d / λ + ∑ RU + ∑ R a + RSi
Ra = afhankelijk van:
1. Dikte luchtlaag
2. Richting warmtestroom
3. Graad van verluchting (matig/niet matig?)

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