100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
Previously searched by you
Summary Task 4 Ordering 2nd revision.docx Task 4 Finite Mathematics Task 4: Ordering Given the following: Let x and y be positive integers when completing part A. A. Explain why it is incorrect to claim that x ˆš y is always irrational. It is incorr$7.49
Add to cart
Summary Task 4 Ordering 2nd revision.docx Task 4 Finite Mathematics Task 4: Ordering Given the following: Let x and y be positive integers when completing part A. A. Explain why it is incorrect to claim that x ˆš y is always irrational. It is incorr
17 views 0 purchase
Course
Wgu
Institution
Western Governors University
Task 4 Ordering 2nd Task 4 Finite Mathematics Task 4: Ordering Given the following: Let x and y be positive integers when completing part A. A. Explain why it is incorrect to claim that x ˆš y is always irrational. It is incorrect to claim that x ˆš y is always irrational b...
task 4 ordering 2nd revisiondocx task 4 finite mathematics task 4 ordering given the following let x and y be positive integers when completing part a a explain why it is incorrect to clai
Written for
Western Governors University
Wgu
All documents for this subject (1238)
Seller
Follow
helperatsof1
Reviews received
Content preview
Task 4
Finite Mathematics Task 4:
Ordering
Given the following: Let x and y be positive integers when completing part A.
x
A. Explain why it is incorrect to claim that is always irrational.
√
y
x
It is incorrect to claim that is always irrational because y may be a perfect square
√
y
which would make the denominator an integer, or a rational number. An irrational number is one
that the numbers after the decimal do not repeat or terminate. If a perfect square is a number that
is the square of a whole number, then not all square roots will be irrational because the square
root of a perfect square is a whole number. A whole number has a decimal that terminates, which
would make it a rational number. So, if x∧ y are both positive integers, and y is a perfect
square then the number would be rational.
Given: 0 <A <B, complete part B.
B. Explain why it is correct to claim that AB
is true.
B <A
It is correct to claim that A<B is true, because B would always be larger than a
B A A
whole and A would always be a fraction of a whole. If A <B, then the fraction A will
B B
always be less than the fraction B. In the fraction A , A would be a part of the whole B,
A B
and when the fraction is inverted to B , then it would become an improper fraction.
A
, An improper fraction has a numerator that is greater than its denominator, and if B > A, then the
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller helperatsof1. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $7.49. You're not tied to anything after your purchase.
