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AER1011 Flight Physics 1Week 6 Tutorial 6 Question Sheet
Answers should be given correct to 2 decimal places.
1. A twin-engined aircraft has a weight of 38,200N, wing area of 27.3m2, aspect ratio of 7.5
with an Oswald span efficiency factor of 0.9. 𝐶𝐷,0 can be assumed to be 0.03. Calculate the
thrust required by the aircraft to fly at a speed of 300km/hr at an altitude of 4km.
300km/hr=83.3m/s
v cl kcl2 cd tr
83.3 0.412361 0.008019 0.038019 2950.322
Thrust required to fly at 300km/hr = 2950.322N
2. A twin jet engined aircraft has a wing area of 47m2, aspect ratio 6.5, e=0.87 with a weight of
103,047N. 𝐶𝐷,0 is 0.032. Each engine is capable of providing 40,298N of static thrust each at
sea-level.
a. Calculate the velocities at which the minimum thrust and power are required for this
vehicle at sea-level.
Answer: Minimum thrust occurs at 2Cd0. Minimum power occurs when CD0=1/3 CDi
𝑾 𝟏𝟎𝟑𝟎𝟒𝟕
For minimum thrust, Cl=0.754, therefore 𝒗𝒎𝒊𝒏𝒕𝒉𝒓𝒖𝒔𝒕 = √ = √𝟎.𝟓∗𝟏.𝟐𝟐𝟓𝟔∗𝟒𝟕∗𝟎.𝟕𝟓𝟒 =
𝟎.𝟓𝝆𝑺𝑪 𝒍
𝟔𝟖. 𝟖𝟖𝒎/𝒔
𝑾 𝟏𝟎𝟑𝟎𝟒𝟕
For minimum power, Cl=1.31, therefore 𝒗𝒎𝒊𝒏𝒑𝒐𝒘𝒆𝒓 = √𝟎.𝟓𝝆𝑺𝑪 = √𝟎.𝟓∗𝟏.𝟐𝟐𝟓𝟔∗𝟒𝟕∗𝟏.𝟑𝟏 =
𝒍
𝟓𝟐. 𝟐𝟔𝒎/𝒔
b. What is the maximum achievable velocity at sea-level?
Answer: Maximum Thrust available at sea-level = 40298*2=80596N. Maximum velocity occurs
when Tr=max Ta.
Either iterate or use graph to solve for vmax = 295 m/s
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