University Of The PeopleMATH 1280BGraded Quiz Unit 8 All Correct Answers
University of the PeopleMATH 1280BGraded Quiz Unit 8 All correct answers
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University of the People MATH 1280B Graded Quiz Unit 8 All correct answers
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University of the PeopleMATH 1280BGraded Quiz Unit 8 All correct answers
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University Of The PeopleMATH 1280BGraded Quiz Unit 8 All Correct Answers
Recall that the population average of the heights in the Òle "" is μ =
170.035. Using simulations we found that the probability of the sample
average of the height falling within 1 centimeter of the population average
is approximately equal to 0.626. From the simulations we also got that the
...
recall that the population average of the heights in the Òle pop1csv is μ 170035 using simulations we found that the probability of the sample average of the height falling within 1 centi
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University of the PeopleMATH 1280BGraded Quiz Unit 8 All correct answers
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3/26/2019 Graded Quiz Unit 8
MATH 1280B Introduction to Statistics - Term 3, 2018-2019
Home ► My courses ► MATH 1280B - AY2019-T3 ► 21 March - 27 March ► Graded Quiz Unit 8
Information
Recall that the population average of the heights in the le "pop1.csv" is μ =
170.035. Using simulations we found that the probability of the sample
average of the height falling within 1 centimeter of the population average
is approximately equal to 0.626. From the simulations we also got that the
standard deviation of the sample average is (approximately) equal to
1.122. In the next 3 questions you are asked to apply the Normal
approximation to the distribution of the sample average using this
information. The answer may be rounded up to 3 decimal places of the
actual value:
m
er as
Question 1
co
Using the Normal approximation, the probability that sample average of
eH w
Not yet answered the heights falls within 1 centimeter of the population average is
o.
Marked out of
rs e
ou urc
1.00 Answer: 0.6272133
o
aC s
vi y re
Question 2 Using the Normal approximation we get that the central region that
Not yet answered contains 95% of the distribution of the sample average is of the form
Marked out of 170.035 ± z · 1.122. The value of z is
ed d
1.00
ar stu
Answer: 1.959964
is
Question 3
Th
Using the Normal approximation, the probability that sample average of
Not yet answered the heights is less than 168 is
Marked out of
sh
1.00 Answer: 0.03486
This study source was downloaded by 100000827039679 from CourseHero.com on 08-09-2021 16:36:53 GMT -05:00
, 3/26/2019 Graded Quiz Unit 8
Question 4 According to the Internal Revenue Service, the average length of time for
Not yet answered an individual to complete (record keep, learn, prepare, copy, assemble and
Marked out of send) IRS Form 1040 is 10.53 hours (without any attached schedules). The
1.00 distribution is unknown. Let us assume that the standard deviation is 2
hours. Suppose we randomly sample 36 taxpayers and compute their
average time to completing the forms. Then the probability that the
average is more than 11 hours is approximately equal to (The answer may
be rounded up to 3 decimal places of the actual value.) 0.07926984 .
Information
Suppose that a category of world class runners are known to run a
marathon (26 miles) in an expectation of 145 minutes with a standard
deviation of 14 minutes. Consider 49 of the races. In the next 3 questions
m
you are asked to apply the Normal approximation to the distribution of the
er as
sample average using this information. The answer may be rounded up to
co
eH w
3 decimal places of the actual value:
o.
rs e
ou urc
Question 5 The probability that the runner will average between 142 and 146 minutes
o
Not yet answered in these 49 marathons is
aC s
Marked out of
vi y re
1.00 Answer: 0.6246553
ed d
ar stu
Question 6 The 0.80-percentile for the average of these 49 marathons is
Not yet answered
is
Marked out of Answer: 146.6832
Th
1.00
sh
Question 7 The median of the average running time is
Not yet answered
Marked out of Answer: 145
1.00
This study source was downloaded by 100000827039679 from CourseHero.com on 08-09-2021 16:36:53 GMT -05:00
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