Tentamen (uitwerkingen)
COS1501 EXAM PACK 2022
- Vak
- Instelling
- Boek
Recent exam questions and answers and summarized notes for exam preparation. or for assistance. All the best on your exams!!
[Meer zien]Voorbeeld 4 van de 94 pagina's
Voorbeeld 4 van de 94 pagina's
In winkelwagen
In winkelwagen
Gekoppeld boek
Titel boek:
Auteur(s):
- Uitgave:
- ISBN:
- Druk:
2 beoordelingen
Door: deadlysin666 • 2 jaar geleden
Door: gertwatson • 3 jaar geleden
Verkoper
Volgen
EduPal
Ontvangen beoordelingen
Voorbeeld van de inhoud
COS1501EXAM PACK
, 2
COS1501
Example examination paper with discussions
SECTION 1
SETS AND RELATIONS
(Questions 1 to 12) (12 marks)
Questions 1 to 8 relate to the following sets:
Suppose U = {1, {2, 3}, 3, d, {d, e}, e} is a universal set with the following subsets:
A = {{2, 3}, 3, {d, e}}, B = {1, {2, 3}, d, e} and C = {1, 3, d, e}.
Before attempting the questions, let us write down the sets U, A, B and C, by adding spaces
between elements, so that common elements are vertically grouped:
U = {1, {2, 3}, 3, d, {d, e}, e}
A = { {2, 3}, 3, {d, e}}
B = {1, {2, 3}, d, e}
C = {1, 3, d, e}
We can clearly see, for example, that element {d, e} in U appears in subset A only. Or that
elements 1, d and e in U, also appear in subsets B and C. Or that the intersection of A and C
contains element 3 only. If you find it difficult to see which elements are in which set, it may
help you to write it in this way on rough in the exam.
Question 1
Which one of the following sets represents A B?
1. {1, 2, 3, d, e}
2. {1, {2, 3}, 3, d, e}
3. {1, {2, 3}, 3, {d, e}}
4. {1, {2, 3}, 3, {d, e}, d, e}
Discussion:
A = { {2, 3}, 3, {d, e}}
B = {1, {2, 3}, d, e}
A B represents the union of the sets A and B. This means, it contains elements that are in A
or in B or in both A and B. (Study guide p. 41).
Thus A B = {1, {2, 3}, 3, d, {d, e}, e}. This corresponds to alternative 4. Remember that the
order of the elements in the set does not matter, as long as all elements are in the set. We
also do not repeat the same element in the set – although the element {2, 3} is in both A and
B, it only appears once in the set A B.
[TURN OVER]
, 3
COS1501
Example examination paper with discussions
Question 2
Which one of the following sets represents B C?
1. {1, 3, d, e}
2. {1, d, e}
3. {d, e}
4. {3, {2, 3}}
Discussion:
B = {1, {2, 3}, d, e}
C = {1, 3, d, e}
The intersection of B and C contains all the elements that are in both subsets B and C, ie
elements that are common in B and C (Study guide p. 42).
Thus B C = {1, d, e}, corresponding to alternative 2.
Question 3
Which one of the following sets represents C – A?
1. {1, {2, 3}, d, e, {d, e}}
2. {3, d, e}
3 {}
4. {1, d, e}
Discussion:
A = { {2, 3}, 3, {d, e}}
C = {1, 3, d, e}
C – A (Set difference / C without A) is the set of all elements that are in C, but not in A (Study
guide p. 42). This means that if an element appears in both A and C, it will be removed from
C to get C – A. It is clear that element 3 is in both A and C and should be removed from C,
thus
C – A = {1, d, e}, corresponding to alternative 4.
[TURN OVER]
, 4
COS1501
Example examination paper with discussions
Question 4
Which one of the following sets represents U + B?
1. U
2. {3, {d, e}}
3. {1, {2, 3}, d, e}
4. (U – A) – C
Discussion:
U = {1, {2, 3}, 3, d, {d, e}, e}
B = {1, {2, 3}, d, e}
U + B (symmetric set difference) is the set of elements that are in U or in B, but not in both
(Study guide p. 43). This means we have to remove the elements that are in both U and B,
which are elements 1, {2, 3}, d and e. We then remain with elements 3 and {d, e}, thus
U + B = {3, {d, e}}, which corresponds to alternative 2.
Question 5
Which one of the following sets represents C B ?
1. {3}
2. {1, d, e}
3. {1, 3, d, e}
4. {1, 3, {d, e}}
Discussion:
U = {1, {2, 3}, 3, d, {d, e}, e}
B = {1, {2, 3}, d, e}
C = {1, 3, d, e}
We first determine B(the complement of B – study guide p. 42). The complement of B is the
set of all elements that is in U but not in B. From the above it is clear that if we remove the
elements 1, {2, 3}, d and e in B from U, we are left with elements 3 and {d, e}, therefore,
B = {3 , {d, e}}. Now we can determine which elements should be in C B.
C B = {1, 3, d, e} {3, {d, e}} = {3}, corresponding to alternative 1. (See definition of
intersection in Study guide p.42).
.
[TURN OVER]
Dit zijn jouw voordelen als je samenvattingen koopt bij Stuvia:
Bewezen kwaliteit door reviews
Studenten hebben al meer dan 850.000 samenvattingen beoordeeld. Zo weet jij zeker dat je de beste keuze maakt!
In een paar klikken geregeld
Geen gedoe — betaal gewoon eenmalig met iDeal, Bancontact of creditcard en je bent klaar. Geen abonnement nodig.
Focus op de essentie
Studenten maken samenvattingen voor studenten. Dat betekent: actuele inhoud waar jij écht wat aan hebt. Geen overbodige details!
Veelgestelde vragen
Wat krijg ik als ik dit document koop?
Je krijgt een PDF, die direct beschikbaar is na je aankoop. Het gekochte document is altijd, overal en oneindig toegankelijk via je profiel.
Tevredenheidsgarantie: hoe werkt dat?
Onze tevredenheidsgarantie zorgt ervoor dat je altijd een studiedocument vindt dat goed bij je past. Je vult een formulier in en onze klantenservice regelt de rest.
Van wie koop ik deze samenvatting?
Stuvia is een marktplaats, je koop dit document dus niet van ons, maar van verkoper EduPal. Stuvia faciliteert de betaling aan de verkoper.
Zit ik meteen vast aan een abonnement?
Nee, je koopt alleen deze samenvatting voor $2.73. Je zit daarna nergens aan vast.
Is Stuvia te vertrouwen?
4,6 sterren op Google & Trustpilot (+1000 reviews)
Afgelopen 30 dagen zijn er 77234 samenvattingen verkocht
Opgericht in 2010, al 15 jaar dé plek om samenvattingen te kopen
Laatst bekeken door jou
College aantekeningen ·
TEMA 2: Neurofisiología
Tentamen (uitwerkingen) ·
MAC2601 EXAM PACK 2022
College aantekeningen ·
Tort Law Lecture Notes
Samenvatting ·
Radiotherapie Periode 5
Samenvatting ·
Tema 2 - Campo eléctrico
Samenvatting ·
SPSS-document analyse 2
Samenvatting ·
Samenvatting IFRS
College aantekeningen ·
Inteligecia Artificial
