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Introduction to Acids and Bases
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intro to acids and basesPH 101-1-1 10 POH
-10911-130+1 log101-1-1 [Hzot ]
-
pH
-
pot to
= =
=
-
-
-
pH +
POH -
-
14 14 pH=
POH
-
14 -
pot
=
pH
ex) [Hsot ] PH POH 101-1 ]
6. 3×10-4 3.2 10.8 1.6×10
-
"
1. 3×10-9 8.9 5. I 7.0×10-6
water equilibrium -
at standard conditions , water is in an equilibrium rxn
"
21120in Hzotlaqi + OH
-1dg) Kc -
-
1.0×10-1
because water is in equilibrium ,
pH changes Ñ temperature
-
we can use Kw to convert between 11-130+1 and 101-1-1
21-12011) 1-130 Tag, +
OH Tag) w
=
11-1307101-11=1.0×10-14
What is the 10th in a solution in pH
:
11.2s 11-130+1 [OH]
6.3×10-4 1.6×10-11 16.3×10-41101-11=1.0×10-14
-
PM 101-1-1
POH 14 10 =
pH
= -
⇒
POH 2.7s
10-2.75 3m01 / L
-
- -
1.8×10
=
P"
1.4×10-97.0×10 -6 (1-130717.0×10-6)=1.0×10-14
11-130+1=10 [1-130+1101-1]
-
⇒ Kw=
10-11-25=5.6×10-12 moly 1.0×10-14 = 1-8×10
'S
Moyd
56¥
acids and bases
strengths of Kw ka Kb
: - -
-
ka very large
strong acids Hlliaq,
ionize thou, ⇒ Hzotlaqi tcliaq)
completely in water :
t
Ka 1.8×10-5
=
!
weak acids ionize
partially measured quantified by Ka Ctlslootllqq, thou, ⇒ tbotag) +4-131001-09 )
+ :
,
strongbases dissociate produce OH directly lmetal hydroxides) NaOH lag)
!
Natiaq, OH Iaq)
-
:
→ +
Ntlytaqi
-
weak base Ñ water to thou + OH Taq )
anything that reacts produce OH ⇒
Ntlzcaq)
-
: +
↳ must have water will have a Kb
,
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