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Statistiek alle opdrachten werkcolleges semester 7
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  • Course
  • Statistiek
  • Institution
  • Fontys Hogeschool (Fontys)
  • Book
  • Statistiek in business voor gevorderden

Dit document betreft een uitwerking van alle opdrachten die in de werkcolleges van Statistiek in semester 7 gemaakt zijn. In de eerste week zijn opdrachten gemaakt uit het Basisboek Statistiek in business en de weken daarna zijn opdrachten gemaakt uit het boek statistiek in business voor gevorde...

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Document information

  • October 6, 2021
  • 10
  • 2020/2021
  • Case
  • -
  • 8-9

Subjects

  • semester 7
  • statistiek
  • formuleren hypothesen
  • bepalen kritieke gebied
  • conclusie trekken
  • nulhypothese
  • minimale steekproefgrootte
  • berekenen toetsingsgrootheid
  • observed frequency expected frequency

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  • Fontys Hogeschool (Fontys)
  • Accountancy
  • Statistiek
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Statistiek Semester 7.1
Alle opdrachten werkcolleges



Werkcollege 1 (wk 1)
Toegepaste opgaven par. 6.10 SIB Basisboek
Opgave 2
a. P (z > 1,23) = 0,1093 = 10,93%
b. P (z < - 1,00) = 0,1587 = 15,87%
c. P (z < 0,50) = 1 – 0,3085 = 0,6915 = 69,15%
d. P (z > -2,01) = 1 – 0,0222 = 0,9778 = 97,78%
e. P (-0,50 < z < 0,25) = 1 – 0,3085 – 0,4013 = 0,2902 = 29,02%
f. P (z = 2) = 0

Opgave 3
a. z = (360.000 – 300.000) / 30.000 = 2
P (z > 2) = 0,0228 = 2,28%

b. z = (250.000 – 300.000) / 30.000 = -1,67
P (z < -1,67) = 0,0475 = 4,75%

c. x 280.000  z = (280.000 – 300.000) / 30.000 = -0,67
x 340.000  z = (340.000 – 300.000) / 30.000 = 1,33
P (-0,67 < z < 1,33) = 1 – 0,2514 – 0,0918 = 0,6568 = 65,68%

Opgave 4
a. x = 13.500
z = (13.500 – 15.000) / 1.000 = -1,5
P (z < -1,5) = 0,0668 = 6,68%

b. x = 14.500
z = (14.500 – 15.000) / 1.000 = -0,5
P (z > -0,5) = 1 – 0,3085 = 0,6915 = 69,15%

Opgave 5
a. Standaardfout = standaarddeviatie / N^0,5 = ^0,5 = 2
z = (37,50 – 35) / 2 = 1,25
P (z > 1,25) = 0,1056 = 10,56%

b. Standaardfout = 2
z = (34,50 – 35) / 2 = -0,25
P (z > -0,25) = 1 – 0,4013 = 0,5987 = 59,87%

Opgave 6
a. Standaardfout = 1,^0,5 = 0,474341649
z = (5 – 6) / 0,474341649 = -2,11
P (z > -2,11) = 1 – 0,0174 = 0,9826 = 98,26%

b. Standaardfout = 0,474341649

, z = (7 – 6) / 0,474341649 = 2,11
P (z < 2,11) = 1 – 0,0174 = 0,9826 = 98,26%

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