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Introduction to mechanical engineering (4GA00) lecture notes $4.82   Add to cart

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Introduction to mechanical engineering (4GA00) lecture notes

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These are the notes per lecture on the course introduction to mechanical engineering from the TU/e.

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  • November 4, 2021
  • 10
  • 2021/2022
  • Class notes
  • Patrick anderson
  • All classes
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Lecture 1




defining mechanical engineering


very broad
"
"
°
A mechanical devices, and realizes new products optimizes existing technologies
and
engineer designs .




examples : cars (engines designs) Shavers , materials to enhance force luggage belts
°

, . ,


°
Subareas of mechanical engineering
-


completional and experimental mechanics
1. mechanics of materials

2.
Microsystems
3.
polymer Technology
-


Thermofluid engineering
1.
energy technology
2. power & flow
-



Dynamical system design
1. control systems technology
& control
2.
dynamics

simple tools


example 1- ladder

% '
e
smooth← ¢ t

when problem take it of salt ( is ladder of realistic ? )
given with a grain 00kg
°
a
mg;§g¥gg_
a
waeey →



y start by drawing a schematic diagram with forces
°
:
FF few
%
.

as
Always (when working with arrows) explicitly state which direction
u
°
e •


mm, ,,,
µ=µ
, ⇐
↳ grass
is positive , a.
¥
problem EÉ= 0 Fx
,

In a static 0 Fy 0

: = =
,


Fw , -

Fµz =
0

FN , FNZ- -
Fwz =
0


for normal forces friction forces
, ,
drawn directions are arbitrary

must calculate torque around a certain point .
Given clockwise is +,

ace forces acting this point have IT 0
torque
-
=
on no


Torque force ✗ arm T-z.EE Fazl Sina
-
=
Cosa -





Introduce variables to see dependencies + Fwlcosa = 0


The arm is the projection ( perpendicular to force direction )





°
Given the wall is smooth FNz<< FN , such that Faiz can be approximated by
, ,
0

-


this leaves you with 3 equations 813 unknowns

FN , Fz 30×9.01 204N
g
=
=
M -
= =




F-w-i-FNz-T-z-E.ee/cosa/esinA
↳ not
dependant on length



example 2- nut cracker

the three parts need to be separated hand




-€ each part is in equilibrium
-




-


Top handle :




(IIF )
/ Fnut


¥
En Faxee + Fnut thanD= 0




nuy
-





I
'

+
-
Fnutt , +F

"
hand






(L ,
+ Lz ) = 0 ( T) Fane Fnut Fane
Fnut =
I •
F- hand

+
Faxee =-3 f-hand
°
To determine the most efficient nutcracker , L , must

be small and Lz large . F- hand
for the given measurements its amplification of 4

an

, dirt
work done power F- at
:




ddt-C-w-7-d-d-IF.xt-dd-E.xtdd-E-T-W-F.gg/x-T
Work :
Using aforceto displace
object

an
>
displacement

the force

same was applied
Work energy principle overtime :dd¥=0
°
-





the best -
case scenario occurs when there's no energy losses
P=F¥=F°v
According
W-in-W-out-W-in-T-inoh-X.in
°
to the work principle ,
energy
-




example 1: pallet Jack





source
Trout -_ Fout ☐
✗ out


Xo =
0cm
side Wont
machine
T-outAXout-F.no/-Xin Win
°

✗ out =
✗ final -
✗0--15-8=7 cm
eoad
Transmission ratio i=F
" ☐ " "t
• =
side
time :
°
Fout : A- ✗ in 4.7s → radius
times levers /
pulled 05
04cm
✗ in =P -3602
° . t
- -




↳ from degreeto
radian


°

t-in-it-out-i.im?j-wei9ht
^




84cm

%
.

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