Exam (elaborations)
Test (elaborations) Mathematics
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this is the memo to the june exam from 2015. use this to check your answers and practice questions you arent sure about. happy studying!
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SENIOR CERTIFICATE EXAMINATION/SENIORSERTIFIKAAT-EKSAMEN
MATHEMATICS P1/WISKUNDE V1
2015
MEMORANDUM
MARKS/PUNTE: 150
This memorandum consists of 19 pages./
Hierdie memorandum bestaan uit 19 bladsye.
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
,Mathematics P1/Wiskunde V1 2 DBE/2015
NSC/NSS – Memorandum
NOTE:
• If a candidate answers a QUESTION TWICE, only mark the FIRST attempt.
• Consistent accuracy applies in all aspects of the marking memorandum.
LET WEL:
• Indien ’n kandidaat ’n vraag TWEE keer beantwoord, sien slegs die EERSTE poging na.
• Volgehoue akkuraatheid is DEURGAANS op ALLE aspekte van die memorandum van
toepassing.
QUESTION/VRAAG 1
1.1.1 x( x − 1) = 0 x = 0
x=0 or x =1 x =1
(2)
1.1.2 2
2x − 4x − 5 = 0
correct
− (− 4) ± (−4) 2 − 4(2)(−5) substitution
x=
2(2) into correct
formula
4 ± 56
=
4
x = −0,87 or x = 2,87 answers
(3)
OR/OF
5
x 2 − 2x − =0
2
completing
(x − 1)2 = 5 + 1 the square/
2 voltooiing van
7 die vierkant
x −1= ±
2
7
∴x =1±
2 answers
x = −0,87 or x = 2,87 (3)
1
1.1.3 5x =
125 5 −3
x
5 = 5 −3
x = −3 answer
(2)
OR/OF
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
, Mathematics P1/Wiskunde V1 3 DBE/2015
NSC/NSS – Memorandum
1
5x = −x 3
125 1 1
−x 3 =
1 1 5 5
= answer
5 5
(2)
−x=3
x = −3
OR / OF
1
5x =
125 use of logs
1
x = log 5
125 answer
= −3 (2)
OR / OF
1
5x =
125
x
5 ⋅125 = 1
5 x ⋅ 53 = 1 53
5 x +3 = 5 0
x+3= 0
x = −3 answer
(2)
1.1.4 (x − 3)(2 − x ) > 0
critical values
– + –
OR/OF
2 3
2 3
solves an
equality
2< x<3
answer
(3)
OR/OF
( x − 3)(2 − x ) > 0
( x − 3)( x − 2 ) < 0
– + – critical values
OR/OF
2 3
2 3
2< x
2< x<3 x<3
(3)
Copyright reserved/Kopiereg voorbehou Please turn over/Blaai om asseblief
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