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Samenvatting Fysica Quark 5.2 thema 5 elektrische schakeling
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Zelfgemaakte samenvatting aan de hand van het boek Quark 5.2 van fysica uitgeverij Van In.
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THEMA 5 ELEKTRISCHE SCHAKELINGEN1) SCHAKELINGEN VAN WEERSTANDEN
● een schakeling oplossen betekent voor elk element bepalen welke spanning
er over staat en welke stroom erdoor gaat
● de hoofdkring bevat de spanningsbron, in knooppunten komen minstens 3
geleiders samen.
2) SERIESCHAKELING
● weerstanden achter elkaar geschakeld
● serieschakeling van weerstanden = spanningsdeler
● in een serieschakeling is de stroomsterkte I in elk punt gelijk (1e wet)
● bronspanning is verdeeld in deelspanningen U ri over de weerstanden Ri, zodat
geldt:
● Ub = UR1 + UR2 + … (2e wet)
2.1) SUBSTITUTIEWEERSTAND VAN WEERSTAND IN SERIE
● de substitutieweerstand Rs van weerstanden R1,R2,R3,… in serie is gelijk aan
de som van de weerstanden: Rs = R1 + R2 + … Rn
3) PARALLELSCHAKELING
● stroom wordt verdeeld over de weerstanden: I = I 1 + I2 + … (1e wet)
● spanning U over elke tak hetzelfde: UR1 = UR2 = … = U = Ub (2e wet)
3.1) SUBSTITUTIEWEERSTAND VAN PARALLELLE WEERSTANDEN
● de substitutieweerstand Rs van weerstanden R1, R2, …, Rn in parallel
bereken je met de formule:
4) GEMENGDE SCHAKELING
● minstens 3 weerstanden in combo van serie- en parallelschakelingen.
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