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Ejercicios de Fundamentos Físicos de la Informática
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Ejercicios de circuitos Thevenin-Norton, corriente alterna, diodos, transistores BJT y FET. Apuntes aparte.
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Física, Eserciciostemor
Ocalculu las intensidades y la potencia disipada en Ri .
In
tv
±:,
-
V ,=12v
•
•
•
{ 2<=2 -
I
to }
133 Rz=4r , >
' to
T
{ 12 V3=5v
'
V
12 = ZR
} } 2 ,
=
I< tz ,
m •
12
,
=3 r
-
3.3 , +4.2 .
-012=3.2-+3.2 , +4.2 ,
→
Is -
¥2 '
( ¥3 ) ( ¥+4 ) y
3i=1↳
'
-
5=2.3 ,
-4.2 .
-0
-
5=2 . .
4.2 → Iii } →
,
P=I .
12=15.4 =9ie
20 Calculators intensidodes
Zs=2÷
mass µ
.
+4=2
oz4-Dzt1fzs@30Cakulalasintensidadesyhrdiferenciadepotencia1entreA.B
.
5{*
In Yin
'
Fb
•
2 +2 =3
Vii 10h ZR
|Z=Is+I
12 , ,
}=
,
"
a , } =+u R Is =
]n+ Is
zr
,
•
"
12 = 1 R ,
I
" ,
"
122=2
I€4A}va=
.
r
↳ _•
• 's
, , ,
10=-2+2.2 , +4 -06=3.2 ,
→
EA Is=ZT
Vis → 2.36=-2.2 ,
→ 36=-3 ,
-
.
Ii=IitZ I,=0hT
(
}r÷+
zr
}r{
a c un →
,
D
o
Wh •
Nf •
3-7=2.2 +52 +43 +1.5+3.2
} + , , ,
,
Sn -
7r
,
CI %
to
's
-4=15.2 , +20 -0 Is .
Its =
-1,67£
T ZA
1,4€
tr
M •
Mr •B
Vab=VAc+VcbtVbb= } '
2+23.4 +7 =
Sr
,# Calculates Yntensidades y In
R
in
4 V
vii :o)
.H
;)
zr nr zr
Hotpoint
m •
m
oottkm ,
• .
z=¥f' =
¥0 =
-0,228T
-
¥i
÷e¥cq⇐ta
Ii :-# :
-0,884.7 In =3 ,
.
Ii .
0,6547
# Calculators intensidades :
in
.IE#tI:i:KtH::tt
1+1
:¥
.
•
.is#=.onnnIz=*u=K=o.uasrIIs=Ki=K=o.stg3QCa1culaladiferenciadPotencia1
I .=¥P"
en los extremes de la fuente de intensidad .
*
.FI#E*iE:*tHty:::IEti
Mr • Mr • 0 -3 14
3A= I ,
-
I ,
1121=1818
a- .
Xiamen In
ftp.t#jeIi.Xi..ikks
3=20*0 .
( ¥jP6| 271 Vx
s +47¥
V×=18,365f
to
, Q ( alcuhn In ,
Vth Y Rtn .
÷e÷
.in#:..EE:tHE::t:iHzs=z=*lv=TaIu=
-0,088€
( :) fiI ) #
3=1,222
V+h€fn
-
.
-
⇐
ftp.#=aaotaVArs.=Vab= 0,407 .
→
Rth =
7+ ( 311 ( 2 t ( 211 (9+3) ) +1 )) +5=12 + ( 311 (3+41112) ) ) = 12+1311 ( st Ff ) ) =
in "¥="#
.ae#e?tw:no...mt!.ntPz.=nVthn=ao9nIp_ogooZQCawaRth
,
In Y V th .
÷E
.at?EwHEIE.E*:x*emw#:xa:mierKHEEtttE.*aii*.teo.E
( ) fi )
's # orienteer
-
no -
.
.
Vaz . = Vac + Ven . =3 V +6 .
0,092 =
}SSzv=Va€
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