Show the calculation of the new temperature of a gas sample which has an original volume of 700 ml
when collected at 730 mm and 35oC when the volume becomes 480 ml at 1.15 atm.
700ml/1000= 0.7 liters= Vi
730mm/700= 1.042 atm=Pi
35 ºC + 273 = 308K = Ti
480ml/ 1000 = 0.04 liters = Vf
1.15 amt= Pf
(1.042) ×(0.7)= (1.15) × (0.04)
(308) Tf
Tf= 12.50 = 17.15K
0.729
-7.0 points
Answer Key
Show the calculation of the new temperature of a gas sample which has an original volume of 700 ml
when collected at 730 mm and 35oC when the volume becomes 480 ml at 1.15 atm.
Exam Page 2
, Show the calculation of the volume occupied by a gas sample containing 0.632 mole collected at 710 mm
and 35oC.
P x V= nxRxT
0.632 mole= n
R= 0.0821
710 mm / 760= 0.934 amt
35 ºC + 273 = 308K=T
(0.921)x V= (0.632) x (0.0821) x (298)
(0.921) x V= 15.462
V = 15.462 = 16.8 liters
0.921
-5.0 points
Instructor Comments
You calculated the pressure as .934 but you are using .921 in your calculation. You are using an incorrect
value for temperature in the calculation.
Answer Key
Show the calculation of the volume occupied by a gas sample containing 0.632 mole collected at 710 mm
and 35oC.
PxV=nxRxT
0.632 mole = n R = 0.0821
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