Ejercicio propuesto. Estequiometría. Química General
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Course
Química General
Institution
Universidad Politécnica Salesiana
Se realizó un planteamiento de un ejercicio donde se pretende encontrar el rendimiento de la solución, además del reactivo limitante y el reactivo en exceso, todo ello a través de la estequiometría.
Si se combinan 10 gramos de Oxígeno con 5 gramos de butano, precisar la
cantidad de agua que se produce, establecer cuál es el reactivo limitante y el
reactivo en exceso.
Indicar el rendimiento cuando en la reacción se han obtenido 3.3 gramos de
H2O.
VALOR CALCULADO – VALOR OBTENIDO
RENDIMIENTO = ------------------------------------------------------- x 100
VALOR CALCULADO
1 mol de O2 10 moles H2O 18 g H2O
10 g O2 x ---------------------- x ------------------------- x --------------------
32 g de O2 13 moles O2 1 mol H2O
= 4,32 g H2O Reactivo limitante
1 mol C4H10 10 moles H2O 18 g H2O
5 g C4H10 x ------------------- x -------------------------- x ----------------
58 g C4H10 2 moles de C4H10 1 mol H2O
= 7,75 g H2O
Se produce 4,32 g H2O. El reactivo limitante es Oxígeno y el
reactivo en exceso el Butano.
4,32 g – 3,3 g
RENDIMIENTO = ----------------------------------x 100 = 23,61
4,32 g
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