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CHEM 120 Week 3 DQ 2 – Molarity and Solution Calculations

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CHEM-120 Week # 3 DQ 2 – Molarity and Solution Calculations Professionals in a scientific laboratory and in the healthcare field need to accurately prepare solutions for a number of reasons. If you wear contacts, you probably use a saline solution to rinse your contacts. What solutions do y...

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  • March 9, 2022
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CHEM-120 Week # 3 DQ 2 – Molarity and Solution
Calculations



Professionals in a scientific laboratory and in the healthcare field
need to accurately prepare solutions for a number of reasons. If
you wear contacts, you probably use a saline solution to rinse
your contacts.
What solutions do you use at work? How would you calculate the
amount of solute to the solvent to prepare this solution?
If you do not wear contacts but you use or make cleaning
solutions for your housework, how would you accurately prepare
solutions to clean?
What solutions do you use that use percent concentration?

, I use apple cider vinegar for multitude of things in my home, from

cleaning my produce, or even taking a shot of it in morning to

help boot my metabolism. It is an essential product in my

household.

The apple cider vinegar I use is already diluted by the

manufacturer to 5% acidity in a 32 FL OZ (946 ml) bottle.

Vinegar is a naturally-occurring liquid that contains many

chemicals, so it can’t just be written in a simple formula.

It has Two main Chemical formulas

H2O (water)

CH3COOH (weak acid – acetic acid)

Apple cider is 5% meaning there are 5 grams of acetic acid in 100

g of solution. I can use mass/mass % to find the total gram of

acetic acid in the bottle. Since there is 946 ml (g) of solution I

need to multiply 946 by 5 divided by 100 (946x5/100) to get the

amount of acetic acid in 946g bottle

946 x 5 = 4730 /100 = 47.3g of acetic acid in 946g bottle of

Apple Cider vinegar

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