Dit is een samenvatting van alle seminars van blok 6 Introductie Statistische Methoden voor Data-analyse met bij elke oefening een brede uitleg. Verder bevat het document op het einde een complete samenvatting van het gele statistiek blok op één A4, die je makkelijk kunt leren voor de bloktoets.
, SEMINAR 1.1
PROBLEM 1: IN A SAMPLE OF WOMEN , THE NUMBER OF CHILDREN THAT EACH
WOMAN HAS , IS AN EXAMPLE OF WHICH TYPE OF MEASUREMENT ?
a. Nominal
b. Ordinal
c. Interval
d. Ratio
D: de hoeveelheid kinderen dat elke vrouw heeft, is het meetniveau ratio. Dit komt doordat het een natuurlijk
nulpunt heeft. Je kunt niet -3 kinderen hebben (nominaal, heeft een willekeurig nulpunt).
PROBLEM 2: IN WHICH SITUATION WOULD THE MEDIAN BE AN APPROPRIATE
MEASURE OF CENTRAL TENDENCY ?
a. When the average is very high
b. When the mode is less than 10
c. When the data are of nominal scale level
d. WHEN THE DATA ARE OF ORDINAL SCALE LEVEL
D: variabelen met een rangorde kun je alleen een mediaan berekenen → 50% van de waarde ligt boven en onder
de mediaan.
PROBLEM 3: WHICH OF THE FOLLOWING IS NOT TRUE FOR A NORMAL
DISTRIBUTION ?
a. MEDIAN IS EQUAL TO THE MODE
b. MODE IS EQUAL TO THE MEAN
c. THE DISTRIBUTION IS SKEWED TO THE RIGHT
, d. APPROXIMATELY 95% OF THE OBSERVATIONS ARE LOCATED BETWEEN THE MEAN
MINUS TWO TIMES THE STANDARD DEVIATION AND THE MEANS PLUS TWO TIMES THE
STANDARD DEVIATION
C: bij een normale verdeling ligt de verdeling mooi symmetrisch in het midden. Bij een verdeling skewed to the
right, spreekt men van een negatieve skewness
PROBLEM 4: WHICH OF THE FOLLOWING IS TRUE FOR A DISTRIBUTION SKEWED
TO THE LEFT ?
a. MEAN IS SMALLER THAN THE MEDIAN , THE MEDIAN IS SMALLER THAN THE MODE
b. MODE IS SMALLER THAN THE MEDIAN , THE MEDIAN IS SMALLER THAN THE MEAN
c. MODE, MEDIAN AND MEAN ARE EQUAL
d. MEDIAN IS SMALLER THAN THE MEAN , THE MEAN IS SMALLER THAN THE MODE
B: bij een positieve skewness ligt de verdeling meer naar links waardoor de modus kleiner is dan
de mediaan en de mediaan kleiner is dan het gemiddelde.
PROBLEM 5: WHICH OF THE FOLLOWING IS TRUE OF A NORMAL DISTRIBUTION ?
a. THE DISTRIBUTION HAS TWO MODES
b. THE DISTRIBUTION IS NOT SYMMETRIC
c. APPROXIMATELY 68% OF THE OBSERVATIONS ARE LOCATED BETWEEN THE MEAN
MINUS ONE STANDARD DEVIATION AND THE MEAN PLUS ONE STANDARD DEVIATION
d. APPROXIMATELY 50% OF THE OBSERVATIONS ARE LOCATED BETWEEN THE MEAN
MINUS ONE STANDARD DEVIATION AND THE MEAN PLUS ONE STANDARD DEVIATION
C: 68% TUSSEN 1
BIJ EEN NORMALE VERDELING LIGT STANDAARD DEVIATION ONDER DE MEAN EN 1
STANDAARD DEVIATION BOVEN DE MEAN (34 + 34)
PROBLEM 6: WHICH OPTION IS THE MEAN OF THE NUMBERS BELOW ?
4544356342
, a. 10
b. 8
c. 4
d. 4.5
C: het gemiddelde wordt berekent door alles op te tellen / het totaal aantal nummers
→ 40/ 10 = 4
Problem 7: Which option is the variance of the numbers below?
4544356342
a. 4
b. 1.33
c. 1.20
d. 1.80
C: variance wordt berekent door:
1) Gemiddelde berekenen: 40/10 = 4
2) Trek van alle nummer het gemiddelde af en kwadrateer: 12
3) Deel deze uitkomst door het totaal aantal nummers: 12/10 = 1,2
- N-1: steekrproef berekenen
- N: totale populatie
PROBLEM 8: IF THE VARIANCE IS VERY LOW
a. THE INDIVIDUALS IN THE DATA SET ARE VERY DIFFERENT FROM EACH OTHER
b. THE STANDARD DEVIATION IS 0
c. THE DATA SET IS TOO SMALL
d. THE INDIVIDUALS IN THE DATA SET ARE VERY SIMILAR TO EACH OTHER
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