Portage Learning CHEM 104 Module 1: Problem Set: General Chemistry 2 with Lab

6/18/2021 Module 1: Problem Set: General Chemistry 2 with Lab


Module 1: Problem Set
Due No due date Points 0 Questions 18 Time Limit None



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Submitted Jun 17 at 2:59pm
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Question 1 Not yet graded / 0 pts


In the reaction of 0.200 M gaseous N2O5 to yield NO2 gas and O2 gas as
shown below:



2 N2O5 (g) → 4 NO2 (g) + O2 (g)



the following data table is obtained:


Time (sec) [N2O5] [O2]


0 0.200 M 0


300 0.180 M 0.010 M


600 0.162 M 0.019 M


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,6/18/2021 Module 1: Problem Set: General Chemistry 2 with Lab

900 0.146 M 0.027 M


1200 0.132 M 0.034 M


1800 0.110 M 0.045 M


2400 0.096 M 0.052 M


3000 0.092 M 0.054 M




(a) Use the [O2] data from the table to calculate the average rate over the
measured time interval from 0 to 3000 secs.

(b) Use the [O2] data from the table to calculate the instantaneous rate
early in the reaction (0 secs to 300 sec).

(c) Use the [O2] data from the table to calculate the instantaneous rate
late in the reaction (2400 secs to 3000 secs).

(d) Explain the relative values of the average rate, early instantaneous
rate and late instantaneous rate.


Your Answer:

.




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, 6/18/2021 Module 1: Problem Set: General Chemistry 2 with Lab




(a) The average rate over the measured time interval from 0 to
3000 secs is:

rate = ∆[O2] / ∆t = (0.054 - 0) / 3000 - 0 = 1.80 x 10-5 mol/L•s



(b) The instantaneous rate early in the reaction from 0 to 300
secs is:

rate = ∆[O2] / ∆t = (0.010 - 0) / 300 - 0 = 3.33 x 10-5 mol/L•s



(c) The instantaneous rate late in the reaction from 2400 to 3000
secs is:

rate = ∆[O2] / ∆t = (0.054 - 0.052) / 3000 - 2400 = 3.33 x 10-6
mol/L•s



(d) It can be seen that the early instantaneous rate is the largest
since the concentrations of reactants is highest during the earliest
stages of the reaction and the late instantaneous rate is smallest
since the concentrations of reactants is lowest during the late
stages of the reaction.




Question 2 Not yet graded / 0 pts


In the reaction of gaseous CH3CHO to yield CH4 gas and CO gas as
shown below:



CH3CHO (g) → CH4 (g) + CO (g)



the following data table is obtained:


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