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CHEM 103 Exam 1-6 Final - Complete Solutions, Graded A $13.49   Add to cart

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CHEM 103 Exam 1-6 Final - Complete Solutions, Graded A

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CHEM 103 Exam 1-6 Final - Complete Solutions, Graded A Exam 1-6 Question 1 1. Convert 1005.3 to exponential form and explain your answer. 2. Convert 4.87 x 10-6 to ordinary form and explain your answer. Answer: 1. Convert 1005.3 = larger than 1 = positive exponent, move ...

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  • April 13, 2022
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  • 2022/2023
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CHEM 103 Exam 1-6 Final - Complete Solutions, Graded
A
Exam 1-6

EXAM 1
Question 1


1. Convert 1005.3 to exponential form and explain your answer.




2. Convert 4.87 x 10-6 to ordinary form and explain your answer.



Answer:

1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3
places = 1.0053 x 103




2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move
decimal 6 places = 0.00000487

Question 2


Using the following information, do the conversions shown below, showing all
work:




1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts




1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints




kilo (= 1000) milli (= 1/1000) centi (= 1/100)

,deci (= 1/10)




1. 2.73 liters = ? ml 2. 8.6 pts = ? qts




Answer:



1. 2.73 liters x 1000 ml / 1 liter = 2730 ml




2. 8.6 pts x 1 qt / 2 pts = 4.3 qts



Question 3


Do the conversions shown below, showing all work:




1. 248oC = ? oK




2. 25oF = ? oC




3. 175oK = ? oF




Answer:



1. 248oC + 273 = 521 oK oC → oK (make larger) +273

,2. 25oF - 32 ÷ 1.8 = -3.88 oC oF → oC (make smaller) -
32
÷1.8

3. 175oK - 273 = -98 oC x 1.8 + 32 = -144.4 oK → oC → oF
oF



Question 4


Be sure to show the correct number of significant figures in each calculation.




1. Show the calculation of the mass of a 17.9 ml sample of chloroform
with density of 1.49 g/ml




2. Show the calculation of the volume of 19.4 grams of cresol with
density of 1.02 g/ml


Answer:
1. M = D x V = 1.49 x 17.9 = 26.7 g




2. V = M / D = 19..02 = 19.0 ml
Question 5


1. 1.35601 contains ? significant figures.




2. 0.151 contains ? significant figures.




3. 1.35601 + 0.151 = ? (give answer to correct number of significant figures)



Answer:

, 1. 1.35601 contains 6 significant figures.

2. 0.151 contains 3 significant figures.

3. 1.35601 + 0.151 = 1.50701 = 1.507 (to the thousands place for 0.151)



Question 6


Classify each of the following as an element, compound, solution or
heterogeneous mixture and explain your answer.




1. Honey




2. Hydrogen iodide




3. Tea




Answer:

1. Honey - is not on periodic table (not element) - no element
names (not compound) appears to be one substance = Solution

2. Hydrogen iodide - is not on periodic table (not element) - has two element
names
= Compound

3. Tea - is not on periodic table (not element) - no element names (not

compound) appears to be one substance = Solution

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