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Samenvatting Antwoorden 6.4 Esters 4 HAVO scheikunde chemie overal
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Antwoorden 6.4 Esters 4 HAVO scheikunde chemie overal
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ó.4 EstersEEgO
aO
il
-c-o
b De naam van een ester is gebaseerd op de beginstoffen waaruit hij is gemaakt: een
carbonzuur en een alcohol.
a een carbonzuur (bijvoorbeeld een alkaanzuur) en een alcohol (bijvoorbeeld een alkanol)
b condensatiereactie
c zwavelzuur of een enzym
d water
m
a
H3C-CH2-CH H en HO-CHz-CHg
butaanzuur ethanol
b
H3C-CH2-OH en HO
ethanol pr0paanzuur
c
H3C-CH2-CH2-OH en
propaan-1-ol ethaanzuur
mr
De ester van ethaanzuur en pentaan-l-ol heeft een grotere molecuulmassa dan de ester van
ethaanzuur en ethanol. Hoe groter de molecuulmassa, des te sterker zijn de vanderwaals-
bindingen tussen de moleculen en des te hoger is het kookpunt.
ago
il
H3C-CH2-C--OH + HO-CH3 +
ll
H3C-CH2-C-O-CH3 + Hro
boo|]i
H-C-OH + HO-CH2-CH3 _+ n-ö-O_C¡tr_cH, + HrO
cOÇHgOCH"
Lt I"
H3C-C-OH + HO-CH-CH2-CH3 _+
ìÍ ï"3
H3C_ö_O*ön_Cnr_CH, + HrO
82 | Hoofdstuk 6
@ Noordhoff Uitgevers bv
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