Exam (elaborations)
MAT1503 - ASSIGNMENT 03 SOLUTIONS (SEMESTER 01 -2022)
- Institution
- Chamberlain College Of Nursng
(a) (i) We shall do this by substitution. Thus 2 (t + 2) + 4 (−2t − 1) + 6t = 2t + 4 − 8t − 4 + 6t = 0 Also 4 (t + 2) + 5 (−2t − 1) + 6t = 4t + 8 − 10t − 5 + 6t = 3 and finally 7 (t + 2) + 8 (−2t − 1) + 9t = 7t + 14 − 16t − 8 + 9t = 6 Thus, x = t+2, y = −2−1,...
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