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Summary Unit 3.3.11 - Amines and Amino Acids (A-level only) $6.46
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Summary Unit 3.3.11 - Amines and Amino Acids (A-level only)

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Summary Unit 3.3.11 - Amines and Amino Acids (A-level only)

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  • August 10, 2022
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Taylor’s Notes Amines and Amino Acids

Amines Nomenclature
Amines contain the functional group R3N where R = an alkyl group or an H

IUPAC Name Skeletal Formula Structural Formula 1°, 2° or 3°




Definition of Methyl, Primary (1°), Secondary (2°) and Tertiary (3°) with respect to Amines
 Methyl CH3NH2 (a special version of a primary amine)
 Primary RNH2
 Secondary R2NH
 Tertiary R3N

Physical Properties of Amines
Amine Solubility
Amines can form hydrogen bonds with water molecules

When carbon chain length increases, the solubility decreases because dispersion forces start to dominate
and disrupt the hydrogen bonding network

Amine Basicity
The strength of the amine depends on the availability of the lone pair of electrons The more available
the lone pair, the stronger the base as the nitrogen must lose a pair of electrons to accept a proton

Compounds with alkyl chains have a positive inductive effect so the lone pair is more available, so protons
are accepted more readily

Compounds with a more electronegative element such as chlorine has a negative inductive effect because
the electronegative element decreases the availability of the lone pair

Compounds with benzene have electrons which are in a -sandwich structure and so are delocalised into
the ring, so the lone pair is much less available

, Taylor’s Notes Amines and Amino Acids

Preparation of Amines
Reduction of Nitriles
Nitriles can be used to synthesise primary amines using LiAlH 4 in dry ether (NaBH4 doesn’t work)

R-C≡N + 4 [H]  R-CH2NH2

Reduction of Nitrobenzene
Nitrobenzene is commonly used to make aromatic amines using Sn/conc. HCl




This reaction is a reduction because you are adding hydrogen

Aromatic amines are used for azo-dyes

Nucleophilic Substitution of Halogenoalkanes
Amines are produced by heating halogenoalkanes in a sealed tube with an excess of ammonia dissolved in
ethanol

A primary amine is formed: CH3CH2NH2 + 2NH3  CH3CH2NH2 + NH4Br

Mechanism for Excess Ammonia with Bromoethane




The primary amine produced has a lone pair and will react with more halogenoalkanes to form a secondary
amine and then a tertiary amine

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