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Ud 1, Balance de Materia
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Balance de materiaA. ? ? ? ? -
( ( II ( (
"""
¡ (( (
e- =
④ SEPT |
'
.
.
.
( ( :| ( (
.
( ( Iii ( ( (
100kg 100kg
Calla
111g / mal
+
Nazcas
106g / mal
☐
Cace , + 2 Nace
☐
Ej .
reacción
,
r -
Reactivos Productos
Reactivo limitante ☐
es el reactivo
que se
gasta antes , en este caso : Narcos
Las reacciones de combustión son
aquellos que incluyen 0-2 [oxígeno ]
5 +
0-2
'
50-2
÷↳
Reactivo Generalmente el -02 se
encuentra en exceso
limitante
, -
? ? ? ? ? -
E jueves
SEPT .
.
•
Torre de destilación ☐
separa dos líquidos que se
evaporan a =/ ta , uno
por
la parte superior
y
otro
por la
parte inferior .
destinado) •
Balance global del : f- =D +
L
¡ proceso
☐
> 800 kg / h B 1500 =
( 800 + ✗) + ( Goo + y) →
✗+y =
100
Caeimentación)
✗
kg / h T
9
•
Cálculo de
F 1500kg / h
D
porcentajes
55% B 55% B •
1500 =
825 kg / h
45% T (líquido )
1 45% T •
1500 =
675 kg / h
(
Goo 1-
>
kglh
y kg / h B •
Balance de B
825=800 + y y 25kg / h
→ =
•
Balance de L
675 Goo ✗ ✗ = 75
kg / h
= →
+
masa total 350+200
550g
* = =
65% A
350g 35% E
> *
> E
550g
> •
Cálculo de
200g
25% A
75% E
> A porcentajes
>
35% de Etanol [ Ms ]
350
122,5g
. =
350 -
122,5g = 227,5
g
de Agua
75% •
200 =
150g de Etanol [ Ma]
•
Masa total de etanol 200 -
15cg =
50g de Agua
M1 + Mz =
122,5 + 150 =
272,5 g
% 100% 49,55% Parcent E
275g E de
. >
.
550g
100%-49,55 =
50,45 % Parcent de A .
, * 45 : 55 =
45kg fresa con 55kg azúcar ( cualquier ud )
↳ Gase de cálculos ,
15% Sóe
es una una
suposición
Fresas HA
.
D De
"
85% A 45kg ✗ > Bsáe .
Azúcar
☐ Sóe =
6,75kg
Manel
¥
.
> 1/3 de la mermelada =
33,5%
Agua → es
55kg • =
y
☐
Azúcar =
55kg ( data directa )
•
Balance global del proceso : 45+55 =
✗+ Y
•
Balance sólidos : 15% •
45kg =
6,75kg
→ 55+6,75 =
61,75 kg
¡
•
Balance mermelada : Si 1- = 33,5% = Sóc .
+
Az .
=
66,5%
de mermelada
% →
en la mermelada
Ee a. 667 de = 61.75 → = 58 %
y Y
'
\ ^
§ qq.gg 30,86 kg de H2O
, =
→ evaporada .
45+55=92,58 ✗ ✗ 7,42 kg Hae
+ → =
Finalmente 45kg de Fresas Necesitaré 0,486kg de F.
kg
}
, si con
•
92,58 de Merrin .
✗ →
1kg de Merm .
77,7% 200kg HzSoy
> •
Balance global : 200kg + ✗ =
Y
resto H2o = 22,3% Y 18,63%
>
Hasty
12,43% ✗ Es Hasty •
Balance Hrsoy
, :
200<77,7%+12,43%1 =
18,63% Y .
-
155,4
¿
}
× _
y +200 =
o
3
W ✗ = 1905,48 kg ¡ Y =
2105,48kg
iré 0,1243 X -
o, 18639 + 155,4=0
, 1,2%
>
✗ kg
→ 4,2% •
Balance global : ✗ +100=9
5,2%
>
100kg
•
Balance de celulosa : 1,2×+5,2 100 . =
4,2J →
0,012 ✗ +
5,2=0,042×+4,2
1
✗= →
33,3kg = ✗
0,03
33,3+100 =
Y →
133,3kg = Y
☐ 70% C
✗
45% Cer
55% A D 30% A
D-
500kg / h Y
☐
Agua evaporada
•
Cálculo de porcentajes
•
Balance global : 500 =
✗+ Y
0,45 c. 500=225
kg / h Cer .
0,55 A -500 =
275kg / h Agua
% %
•
Balance H2O : 0,55 .
500 =
Y +
OBX
% %
•
Balance Cereales : 0,45-500=0,7 ✗ > 225=0,7 ✗ ☐
✗ = 321,43 kg / h
Y =
500-321,43 ☐
y= 178,57kg / h
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