MATH 110 Final Exam Questions and Answers 2023- Portage Learning

MATH 110 Final Exam Questions and Answers- Portage Learning 2022 In a tri-state conference, 60% attendees are from California, 25% from Oregon, and 15% from Washington. As it turns out 6 % of the attendees from California, 17% of the attendees from Oregon, and 12% of the attendees from Washington came to the conference by train. If an attendee is selected at random and found to have arrived by train, what is the probability that the person is from Washington? P(Train│C)=.06.. P(Train│O)=.17.. P(Train│W)=.12.. P(C)=.60,P(O)=.25,P(W)=.15. We want to find P(W│Train), so use: Question 4 Find each of the following probabilities: a. Find P(Z ≤ -0.87) . b. Find P(Z ≥ .93) . c. Find P(-.59 ≤ Z ≤ -.36). a. P(Z ≤ -0.87)= .19215. b. P(Z ≥ .93)=1- .82381= .17619. c. P(-.59 ≤ Z ≤ -.36)= .35942- .27760= .08182. Question 5 Suppose that you are attempting to estimate the annual income of 1700 families. In order to use the infinite standard deviation formula, what sample size, n, should you use? In order to use infinite standard deviation formula, we should have: n≤0.05(1700) n≤85 So, the sample size should be less than 85. Question 6 A shipment of 450 new blood pressure monitors have arrived. Tests are done on 75 of the new monitors and it is found that 15 of the 75 give incorrect blood pressure readings. Find the 80% confidence interval for the proportion of all the monitors that give incorrect readings. Answer the following questions: 1. Multiple choice: Which equation would you use to solve this problem? A. B. C. D. E. 2. List the values you would insert into that equation. 3. State the final answer to the problem We have a finite population, so we will use Case 2: E. The proportion of the sample that are defective is 15/75 = .2 so we set P=.2. As we mentioned previously, we estimate p by P. So, p=.2. A total of 75 monitors were tested, so n=75. Based on a confidence limit of 80 %, we find in table 6.1 that z=1.28. The total number of monitors is 450, so set N=450. Now, we can substitute all of these values into our equation: