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Samenvatting Natuurkunde newton h3 beweging

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samenvatting natuurkunde newton h3 beweging 4 vwo

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  • December 5, 2022
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  • 2020/2021
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H3 natuurkunde beweging



Soortelijke warmte= hoeveelheid energie (J) er nodig is om 1 kg van een stof 1 graad te verwarmen



Water: c= 4,18 x 10^3 J/kg x K

Om 1 kg water 1 graad in temperatuur te laten stijgen, heb je 4180 J nodig

Bij 2 kg water= 8360 J

Bij 1 kg water, 2 graden= 8360 J



Q= c x m x delta T

- Q= warmte in Joule (J)
- c: soortelijke warmte (J/kg x K) (binas)
- m: massa in kilogram (kg)
- delta T= temperatuurverschil Teind – Tbegin (K)



stel je verwarmt 100 gram water van 10 naar 20 graden Celcius

- bereken de hoeveelheid warmte die door het water is opgenomen in kWh

tabel 5= omrekenfactor kWh



stap 1= m= 100 g  0,010 kg

tb= 10 graden celccius

te= 20 graden celcius

c= 4,18 x10^3 kg x K

stap 2= Q = ? J

stap 3= Q= c x m x delta T

Q= 4,18 x 10^3 x 0,01 x 10

Q= 4,2 x 10^2 J

1 kWh = 3,6 x 10^6 J

Q= 4,2 x 10^,6 x 10^6 = 1,2 x 10 ^-4 kWh

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