Summary
Samenvatting Wiskunde formuleblad
- Course
- Institution
Op dit formuleblad staat alles wat je moet weten voor wiskunde 1e jaar Life Sciences aan de hogeschool Utrecht.
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Jylan13
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Formuleblad wiskundeRekenvolgorde Logaritmen
1) Haakjes
2) Machtsverheffen
glogia
I I
log (a) -
log (aY p.
=
Blog (d)
3) Worteltrekken
4) Vermenigvuldigen
5) Delen
-log (a.b) 0 =
log (a) +
Flog(b) a
=
yx
=
log(y)
6) Optellen Blog (B) =
"log (a) log(b)
7) Aftrekken
Hoe Moeten Wij Van De Onvoldoendes Afkomen?
ABC-formule. Formule v/d top
bergparabool 0 dalparabool
x-bIa
0 a =
T
=
a
Breuken optellen en aftrekken
1) Noemers gelijk maken
xtop=.a ytop =
xtop invullen in formule
Asymptoten
sAD B3ER AD BER
BC
+P
#
+
AD,t C
* AD,BC Horizontale asymptoot = groot getal invullen
Verticale asymptoot = noemer gelijkstellen aan 0
Ac, A B
C
Snijpunten met de assen
T
*
+c +
P gA BC
,
A
TB
C
c A
1
Snijpunt Y-as: x=0
3 63 48,820103365420
+ + 16 5 E Snijpunt X-as: Y=0
Breuken vermenigvuldigen
Opstellen van een raaklijn
A xB A Y = ax + b. A = RC. B= asafsnede
1) Bepaal de afgeleide van de functie
*
x c A Alx
2) Bereken de a door s in te vullen in de afgeleide functie
Breuken delen 3) Bereken y door x in te vullen in de oorspronkelijke functie
1) stel je wilt een breuk delen, dan moet je vermenigvuldigen met het 4) Bereken b door x en y in te vullen in de oorspronkelijke
omgekeerde! functie
5) Stel de vergelijking van de raaklijn op: y= ax + b
Ms +
A
Differentieren
A Ax
As
E
f(x) 2.182x+1. In
+ 1
f(x) 102x
f(x) 18
=
c
= 0
=
f(x) lnaxb f(x) E
5f'(x)
= =
0
Breuken omklappen f(x)
=
f((x) x
=
f(x) lxx
=
=
f'(x)
1
f(x) f(x) (n(2x3 3x)f(x) c031
n -
ax
1,
n.ax
B
=
n
↑= b A
+
=
=
=
=
- =
2 =
B
5
f(x) eaX f'(x) a.ex f(x) (n*f(x) ictx 2x
=
=
=
=
=
Machten f(x) 8log(X) f'(x) xing
f(x) ef'(x) eX
=
=
=
=
f(x) 2xe* f(x) log(5x 8'(x) 5,n3 xins
=
am f(x) e-
=
=
R
qM.qn qm
+
=
=
n
am
= -
=
an
f(x) 8'(x) 3n3 f(x) 3.log log xf'(x) xPnio
= =
n 3
=
= =
am.qh -m an
-
aretaubin= f(x) gaf'(x) a.g*Ing f(x) lnaxf(x) 0
= =
= =
(am) ym.n =
Som regel
(ab)" ab
=
a 1
=
f(x) h(x)
=
+
g(x)
f(x) h(x)
=
+
g(x)
Omschrijven van vergelijkingen
Product regel
a = by c ad
= -
b
f(x) g(X).h(x)
=
a
c + d c =(b- ad) h(X)
f(x) g'(X)-h(x) g(x).
=
a
=
+
a b + b(ab 1)
Quotient regel
=
c =
-
E b +
g(X)
bf(b f)
v
f(x) h(X)
=
-
=
=
h(X)
g(x).
f(x) a(X).h(x)(h(x))2
-
Wortels
=
ra.B=2 a = F Ketting regel
Afgeleide buiten de haakjes x haakjes x afgeleide tussen haakjes
a y b
=
an =
f(x) g(h(x))
=
f(x) g(h(X)).h(x)
=
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