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Zusammenfassung Mathematik J1/3 $12.82   Add to cart
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Zusammenfassung Mathematik J1/3
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  • Course
  • Mathematik
  • Institution
  • Gymnasium

In dieser Zusammenfassung, aus dem zweiten Halbjahr aus J1, habe ich anhand von Beispielaufgaben und bildlicher Veranschaulichung verschiedene Thematiken aus dem Mathematik Unterricht zusammengefasst und veranschaulicht.Durch diese sind die genannten Thematiken leicht zu verstehen und einfach zu er...

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Document information

  • January 24, 2023
  • 8
  • 2021/2022
  • Summary

Subjects

  • optimierungsaufgaben
  • stammfunktionen
  • bestimmte integral
  • aufstellen von kurvengleichung
  • mathematische modellierung

Written for

  • Secondary school
  • Gymnasium
  • Mathematik
  • 2
All documents for this subject (384)

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cekarak

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:

, Beispiel:

Das Schaubild einer ganzrationaler Funktion 3. Grades schneidet die y-Achse im Punkt Sy(0/1), verläuft durch den Punkt P(1/ ) und hat den
Hochpunkt H(-2/5).
Bestimmen Sie den Funktionsterm.

Ansatz: ƒ(x)= ax + bx 2 + cx + d 3




ƒ(x)= 3ax + 2bx + c 2




Sy(0/1): f(0)=1: 0a+0b+0c+d=1 (1)


s
LGS
P(1/ ): f(1)= : a + b + c + d= (2)
4Unbekannte
2


H(-2/5): f(-2)=5: -8a+4b--2c+ d=5 (3)
4Gleichungen
zwei
f´(-2)=0: > 12a—4b+c =0 (4)
Möglichkeiten




Lösen das LGS aus (1): d=1 einsetzen in (2) (3) (4)

a + b + c + 1 =7
-8a + 4b — 2c + 1 = 5 In vernünftige Form (Alle Buchstaben Links / Zahlen Rechts)
12a — 4b + c = 0



a + b + c = — 2
08 • ( -12 )

-8a + 4b — 2c = 4 +


12a — 4b + c = 0 +




a + b + c = —
2

12b + 6c = 0 • ¥ ± §
-16 — 11c= 6 +




a + b + c = —
2-
12b + 6c = 0
Dreiecks
— 3c = 6
Form


Letzte Zeile: -3c = 6 I:(-3) Zeile 2 : 12b — 12 = 0 Zeile 1: a + 1 — 2 = — 2-
c = —2 12b = 12 a=£
b=1



=> Ergebnis: ƒ(x)= x + x — 2x + 1
3 2

g.

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