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NATE Exam: Core Essentials | 121 Questions with 100% Correct Answers
- Course
- NATE
- Institution
- Liberty University
NATE Exam: Core Essentials | 121 Questions with 100% Correct Answers
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NATE Exam: Core Essentials1.d (very important): The ability to utilize all types of communication skills is to the HVACR technician.
a.not as important as "hands-on" technical skills
b.somewhat important
c.unimportant
d.very important
2.d (all of the above: clear, complete, concise): It is important to be in filling out service orders so that office staff, other technicians, and customers will know what work you completed on the job.
a.clear
b.complete
c.concise
d.all of the above
3.d (Refrigerant): When explaining to a customer that you have adjusted the system charge, which of the following terms is most appropriate?
a.Freon
b.Gas
c.Juice
d.Refrigerant
4.a (can help you diagnose the problem): Listening carefully to what a customer is telling you .
a.can help you diagnose the problem
b.is a waste of time
c.is not necessary
d.often will only confuse you
5.b (listen to the customer first, then ask questions): When you arrive at a service call and meet the customer, you should .
a.ask questions first, then listen to what the customer has to say
b.listen to the customer first, then ask questions c.avoid discussion with the customer
d.remind the customer that you are the professional and get on with your work .b (1,600 ft3): What is the volume of a room that measures 10 ft by 20 ft with an 8-ft ceiling?
a.800 ft3
b. 1,600 ft3
c. 2,400 ft3
d. 3,200 ft3
7.b (1,200 CFM): What is the CFM requirements for an 1,800-ft2 house with 8-ft ceilings, if five air changes per hour are needed?
a.400 CFM
b.1,200 CFM
c.1,600 CFM
d.2,400 CFM
8.c (1,600 CFM): What is the CFM requirement for an 2,400-ft2 house with 8-ft ceilings, if five air changes per hour are needed?
a.400 CFM
b.1,200 CFM
c.1,600 CFM
d.2,400 CFM
9.a (79 in2): What is the cross-sectional area of a 10-in round metal duct?
a.79 in2
b.200 in2
c.314 in2
d.418 in2
Note: Area of a circle = À x radius^2
10.d (1,800 ft/min): How fast does air with a velocity pressure of 0.20 in. w.g. move through a round duct?
a.400 ft/min
b.1,200 ft/min
c.1,600 ft/min
d.1,800 ft/min Note: Velocity = 4005 x (the square root of velocity pressure)
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