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Samenvatting Wiskunde 1ste jaar BMLT
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  • Course
  • Wiskunde
  • Institution
  • Hogeschool Gent (HoGent)

Samenvatting Wiskunde 1ste jaar Biomedische Laboratoriumtechnologie (BMLT). Docent Annelien Sercu. Hoofdstukken goniometrie, vergelijkingen en stelsels van vergelijkingen, lineaire functies, exponentiële en logaritmische functies en vergelijkingen, limieten, afgeleiden en integralen.

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Document information

  • February 3, 2023
  • 23
  • 2020/2021
  • Summary

Subjects

  • wiskunde
  • goniometrie
  • vergelijkingen
  • lineaire functie
  • limieten
  • afgeleiden
  • integralen
  • stelsels van vergelijkingen
  • exponentiële en logaritmische functies en vergelijkingen

Written for

  • Hogeschool Gent (HoGent)
  • Biomedische Laboratoriumtechnologie
  • Wiskunde
All documents for this subject (19)

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GONIOMETRIE

ALGEMEEN

cos ❑


sin


sin❑ 1 tan α . cotanα =1
tan¿ tan¿
cos ❑ cot❑


1 cos❑ 1
cot ¿ =¿ ¿ cot ¿
tan sin❑ tan❑


1
sec¿
cos ❑


1
csc=
sin ❑




FORMULES

sin 2 +cos 2=1 sin 2 =1−cos 2
2 2
cos =1−sin

2
1
sec 2 α = 2
=1+tan (cos 2 α ≠0 ¿
cos α

2
1
csc 2 α = 2
=1+cot (sin 2 α ≠ 0 ¿
sin α


tan α
sin α =±
√1+ tan2 α

1
cos α=±
√1+ tan2 α

,MERKWAARDIGE PRODUCTEN




GONIOMETRISCHE GETALLEN

, VERWANTE HOEKEN


1) GELIJKE HOEKEN 1) TEGENGESTELDE HOEKEN


sin ( α )=¿ sin ( α +360 ° ) sin (−α )=¿ −sin ( α )


cos ( α )=¿ cos ( α +360 ° ) cos (−α ) =¿ cos ( α )


tan ( α )=¿ tan ( α +360 ° ) tan (−α ) =¿ −tan ( α )


cot ( α )=¿ cot ( α +360 ° ) cot (−α )=¿ −cot ( α )




2) SUPPLEMENTAIRE HOEKEN 2) COMPLEMENTAIRE HOEKEN


sin ( 180 °−α )=¿ sin ( α ) sin ( 90 °−α )=¿ cos ( α )


cos ( 180 °−α ) =¿ −cos ( α ) cos ( 90°−α )=¿ sin ( α )


tan ( 180 °−α ) =¿ −tan ( α ) tan ( 90°−α )=¿ cot ( α )


cot ( 180 °−α )=¿ −cot ( α ) cot ( 90 °−α ) =¿ tan ( α )




5) ANTISUPPLEMENTAIRE HOEKEN 6) ANTICOMPLEMENTAIRE HOEKEN


sin ( 180 °−α )=¿ −sin ( α ) sin ( 90 ° +α )=¿ cos ( α )


cos ( 180 °−α ) =¿ −cos ( α ) cos ( 90°+ α )=¿ −sin ( α )


tan ( 180 °−α ) =¿ tan ( α ) tan ( 90°+ α )=¿ −cot ( α )


cot ( 180 °−α )=¿ cot ( α ) cot ( 90 °+α )=¿ −tan ( α )

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