Class notes
Colección de problemas de Estática del Sólido (1/3)
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Incluye problemas resueltos de Estática del Sólido.
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✗y
Dls :?)
ds . M
^
8
A s <
• M
1
[
2
<
a 12/2
1-
R
B Is -
-
-
)
M 6m
>
Os °
×
, t coordenadas
generalizadas X, B
•
:
, O
•
) Incógnitas de contacto :
a) Del exterior sobre el aro (1) i
Resultante : IÉ" = Xí +
Yj
sistema de fuerzas de contacto del exterior sobre 111 :
Momento : Ñ% = j
b) Entre 111 121 :
y
Fuerza de contacto de (1) sobre 121 :
✗ y
a
Frñp
C
EH = Nír +
FRÚP
P •
1 T
Núr
¡
Fuerza de contacto de (2) sobre 111 :
•
Es < p
'
Nar
t
ÉRUP
-
Tir
-
9s X
≥
◦
¡2/1 = -
Núr -
ÉRUP
Incógnitas de contacto : X Y N FR. , ,
•
| Fuerzas directamente aplicadas : Atracción del eje Ox proporcional 1kt a la masa Y a la distancia al eje Ox .
a) Sobre el aro 111 :
"
"
E = -
km
y j
= -
km
Rsenxj
b) Sobre las masas del disco (2) :
""
[ / Otfbl ] dsj
ÉAT Kdm Yj kdm
3212 senfs + ssen
= -
= -
-
dm = tds
dm = 6m
ds
R .
y =
OM.j-loi-CMI.gs/R+PzlsenB-ssen/O- A)
Momento respecto al punto G
'
de EHF :
dm
6,1 [ 3¥ senptssen / ABI !
"m
Ñ = CMAÉAT =/ scos / 8-psli ssenlotpslj ] a F- Atdm
+ = -
K s costo + Btdsk
Resultante del sistema de fuerzas de atracción sobre las masas del disco :
EAT =/ EAÍM = -
K / / Ydm / Í '
ÉAT = -
K 6m
3¥ senpsj
MIA KMRZsentamos lo B) !
E s +
-
z
YC
'
312
senp 6m Y → =
a
2
Momento resultante del sistema de fuerzas de atracción sobre las masas del disco :
12/2 12/2
"
MIA? / dmpjí ≥
"'
pj , = /sds
-1<6,11%2 senp costo AlRt + + sen /HA/ costo-11/ Ids / Í
-
-
12/2
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