Class notes
Colección de problemas de Sistemas Abiertos
- Course
- Institution
Incluye problemas resueltos de Sistemas de Abiertos.
[Show more]
Seller
Follow
AeroLibrary
Content preview
ARCIAL 2021-2825↑
*= 20ms -- 406 Pg
Mi0B = 0.92
=
=288%C
↑
↑F = 98KPa
P5 188KPa
=
T3 T2 + 388K
=
↑=287,151 Pn P3 P2
=
=
- A, SMW
↑1 = 98KPa
12= 15
1c 0,89
=
1.n gw.A PF =
=
.x+ = 98.183 Pa 20m3. s7 · = in 14,44kg/S
=
Rg. T 286.975kg 17.473,15K
-
8,3745.mp17.157
286,975kg+17
Ru
Rg =
= =
M
28.97.18-3kg/mo
↑F
4 +3,15
1 T06
-0.92 =1-
T00
-
2. 450B 1:566 554.5k
-
= -
↓-P 6 =
7
1 -
98.1637.4.
1,4
PsG 188-183
554,5k 473,75k + 484,57m/s
wh
Tx T7 =
+ = =
w
- =
2.1.885
3. Pn=P3 = Pe =
1,5. P1 = 7.5.98KPa= F35KPa
8-1 1.4 I
P2 -
40-1
=
0,89 =
7.5 5,4
-
T2 538,28K
x
- =
T2 T2
-
I -
I
↑
I 287,15
-vivneto-mcp(T2-+1) m(p(55 + -
+h) =
Tn 1,8.100
=
+ +2+1 + Ts
n <p
Balance energetical cambiador decalor: m(hc hs) + m(hs- h2) 0 -
=
im(p(T0-Ts) + m(p(13-+2) 0
=
= T5 T6 + T3- Tz
=
↑5 554,5k + 588K 854,5K
=
=
T4 1.8.106
=
538,28K 287,15 + 854+Th 1.238K
+ -
=
14,44. 1.885
854K
1
-
1
- 1.230k
4.17 =
- 47 0,92 =
88.7831,4-5
is ofre
*
1, Y
=
35.183 -
I
ii
-
5. s =
+
up
TFT
o sond=0
0-5. Chanain
Balanceenergeticalacamaradecombustion: m ci n tul O i w hunzoos(coo. 287,15 #
50O
I
-
Tt T+= +
w 554,5
=
, PARCIAL 2018-2019
A0 0.58m3
=
Po Pox
=
To3 = 1.FOOK
P03 = 0,98P32
1 TO B 6
FTCC
4 5
↑
- -
2 5
PGB
C T T2 Wh
M B
/ I
T81 249K =
7 0.88
=
s=63.4" 8 0.02Wh
=
101 52592Pa/W+1) wc+5 +45k
=
=
=
PO2 Ta
*
= 24
↑
Pos =258K
7 8,86
=
1
Poe 32.952Pa.24 =
+P02 =
= 90.848Pa
6-1
1,4 1
1081
-
24 714, 1 T02 67,33K
=
n 0,86: -
=
-
TO2 TO2
-
I -
1
To1 249
2. Pos = 0.98.P02 = = 5.031,84Pa
-
wTs wc =
-+
-m(p1T02-+xx) m(p)Ton =
- T03) Toh T01 T62+ T03
= =
-
= Ton 249k
=
-
677,33k + 1.t00K,Ton 1.271.67K
=
1.271,67
I
jobo
-
TO O
1
Pon =
238.886, 14Pa
n + 8,88 =
- ·
-
1.4 1
POU
-
O
1, Y -
I
Pos -> 5.831,84
#
s Pos 29.541,5 Pa
As-<pIntos-RgInPos
3. In 735K-28tIn
=
63.45/kgk
-
= 6.805
1.271,67K 238.806,14Pa
i36+
to5
+
1 y7 0,92
-
-
= =
29.547.51.4- 1
POG
-
I 1.4,1
238.006,14
249K-194,44"m/s
T00-wha
4. 560 = - + To =238,2K
2.1.885
⑧
1
M
P0 P0a =
↑88
6I
- 32.952 230.2 1.47;P00 P0 =
= 25.855,3Pa
T8x 24d
TO TG
1 -
105 1
-
F45 T6 11,97K
M+0B
-
1 = - =
=
25035,31.4 7
↓toa
-
1 -
1, 4
29.541,5
100w
we 25+.66m/s
3. T6 = =
+77,9+k = +451 -
+ w =
2.1.885
1.w.A 18,31k as
n = 25.035,34a. 25+,66.0,58
=
n
+
=
28+. 11,97
The benefits of buying summaries with Stuvia:
Guaranteed quality through customer reviews
Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.
Quick and easy check-out
You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.
Focus on what matters
Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!
Frequently asked questions
What do I get when I buy this document?
You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.
Satisfaction guarantee: how does it work?
Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.
Who am I buying these notes from?
Stuvia is a marketplace, so you are not buying this document from us, but from seller AeroLibrary. Stuvia facilitates payment to the seller.
Will I be stuck with a subscription?
No, you only buy these notes for $6.88. You're not tied to anything after your purchase.
Can Stuvia be trusted?
4.6 stars on Google & Trustpilot (+1000 reviews)
48298 documents were sold in the last 30 days
Founded in 2010, the go-to place to buy study notes for 15 years now