(a) (i) 1/R total = 1/(40) +1/(10+5) = 0.09167
2 R total = 10.9 kΩ
3
(ii) I = .9 k = 1.1 mA
1
(b)
position pd / V
AC 6.0
DF 4.0
CD 2.0
C.E. for CD
3
(c) (i) AC: no change
constant pd across resistors / parallel branches(AE)
no CE from first mark
2
(ii) DF: decreases
as greater proportion of voltage across fixed / 10 k Ω resistor
no CE from first mark
2
[11]
(a) 1 joule per coulomb (or equivalent)
3
B1
allow watt per amp
1
(b) (i) Use of potential divider formula
C1
allow 1 for 4.05 (V) or current of 2.25 (mA)
4.95 (V)
A1
2
(ii) reduced current
B1
1
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(iii) use of parallel resistor formula
C1
leading to 1.72 (kΩ)
C1
pd = 4.4 (V)
A1
3
(iv) potential divider can provides sensitive control of current (from 0 - 1.1 mA)
B1
allow pot div can provide zero current and variable resistor gives
larger current
variable resistor can provide larger current but cannot get near 0 A owtte
B1
2
[9]
(a) potential divider or potentiometer
4
B1
1
(b) minimum 4 (V)
B1
variable R 8Ω
B1
max I 12 V
B1
variable R 0 (Ω)
B1
4
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Page 21 of 31
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