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CHEM 103 Lab Exam 3 – Portage Learning
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CHEM 103 Lab Exam 3 – Portage Learning. A 1.1000 gram hydrate sample chosen from Na2CO3∙10H2O, AlCl3∙6H2O, MgCl2∙6H2O and BaCl2∙2H2O was heated and found to lose 0.5841 gram of H2O. (1) Show the calculation of the % H2O in the unknown hydrate sample. (2) Show the calculation of the % H2O in each of the hydrate compounds and identify the unknown hydrate from the list. Atomic weights: H = 1.008, O = 16.00. MWs: Na2CO3∙10H2O = 286.15, AlCl3∙6H2O = 241.43, MgCl2∙6H2O = 203.301 and BaCl2∙2H2O = 244.462 % H2O in unknown = (0.5841 / 1.1000) x 100 = 53.10% % H2O in MgCl2∙6H2O = 108.096 / 203.301 x 100 = 53.17% unknown is MgCl2∙6H2O Answer the following two questions:
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Institution
Portage Learning
Course
CHEM 103 Chemistry (CHEM103)
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Portage Learning
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CHEM 103 Chemistry (CHEM103)
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- Uploaded on
- March 23, 2023
- Number of pages
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- Written in
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- chem 103
- chem
- chem 103 chemistry
- chemistry
- chem 103 lab exam 3
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chem 103 lab exam 3 – portage learning
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