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HW4 Solution - F19 University of Michigan EECS 484
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Question 1 (20 points) 2.1) (4 points) B - 1 buckets 2.2) (4 points) Recursively apply hash-based projection technique to further split the buckets with different hash functions until no more partition overflow. 2.3) (4 points) (B - 1)^2 buckets 2.4) (4 points) Accelerate the record matching i...

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  • March 30, 2023
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  • 2022/2023
  • Exam (elaborations)
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  • hw4 solution f19 university of michigan eecs 484
  • question 1 20 points 21 4 points b 1 buckets 22 4 points recursively apply hash based projection technique to further split the buckets w

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  • EECS 484 Database Mgt Syst
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Question 1 (20 points)

2.1) (4 points) B - 1 buckets

2.2) (4 points) Recursively apply hash-based projection technique to further split the buckets with
different hash functions until no more partition overflow.

2.3) (4 points) (B - 1)^2 buckets

2.4) (4 points) Accelerate the record matching in memory or reduce CPU cost of record matching.

2.5) (4 points) No. In the probing phase, using the same hash function will assign each data record into
the same bucket. No speeding up for join in the probing phase is obtained by using the same hash
function.



Question 2 (20 points)

1.1) (6 points)
Block Nested Loops Join
(A) Reads = |R| + |S| * ceil(|R|/(B-2)) = 5,000 + 20,000 * ceil(5,000/(600-2)) = 185,000
(B) Writes = 0 (no writes are required for nested loops joins)

1.2) (7 points)
Grace Hash Join
(A) Reads in Partition phase = |R| + |S| = 25,000
Reads in Probe phase = |R| + |S| = 25,000
Total reads = 2 * (|R| + |S|) = 50,000
(B) Total writes = |R| + |S| = 25,000

1.3) (7 points)
BNJ = 185,000 * 1.5 [reads; no writes] = 277,500
GHJ = 50,000 * 1.5 [reads] + 25,000 * X [writes]
From BNJ = GHJ → 277,500 = 75,000 + 25,000 * X
we get X = 8.1
So we should choose BNJ if X > 8.1 , but GHJ if X < 8.1




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