,Why do we study logarithms: Sometimes multiplication, subtraction and exponentiation
become so lengthy and tedious to solve. Logarithms covert the problems of multiplication
into addition, division into subtraction and exponentiation into multiplication, which are easy
to solve.
Properties of Logarithms: If 𝑎, 𝑏 and 𝑐 are positive real numbers, 𝑎 ≠ 1 and 𝑛 is any real
number, then
For example: 𝑙𝑜𝑔 = 𝑙𝑜𝑔 51 − 𝑙𝑜𝑔 7
3. Power property: 𝒍𝒐𝒈𝒂 𝒃𝒏 = 𝒏. 𝒍𝒐𝒈𝒂 𝒃
For example: 𝑙𝑜𝑔 (10000) = 𝑙𝑜𝑔 (10 ) = 4. 𝑙𝑜𝑔 10
4. One to One property: 𝒍𝒐𝒈𝒂 𝒃 = 𝒍𝒐𝒈𝒂 𝒄 if and only if 𝒃 = 𝒄.
For example: If 𝑙𝑜𝑔 (𝑎) = 𝑙𝑜𝑔 (15) then 𝑎 = 15.
5. 𝒍𝒐𝒈𝒂 𝟏 = 𝟎
For example: 𝑙𝑜𝑔 (1) = 0 , 𝑙𝑜𝑔 (1) = 0 , 𝑙𝑜𝑔 (1) = 0 etc.
6. 𝒍𝒐𝒈𝒂 𝒂 = 𝟏
For example: 𝑙𝑜𝑔 (10) = 1 , 𝑙𝑜𝑔 (𝑒) = 1 etc.
7. 𝒍𝒐𝒈𝒂 𝒂𝒏 = 𝒏
For example: 𝑙𝑜𝑔 10 = 4
8. 𝒂𝒍𝒐𝒈𝒂 (𝒏) = 𝒏, where 𝒏 > 0
( )
For example: 2 =8
𝒍𝒐𝒈(𝒃) 𝒍𝒐𝒈𝒄 (𝒃)
9. Change of base property: 𝒍𝒐𝒈𝒂 𝒃 = = provided that 𝒄 ≠ 𝟏.
𝒍𝒐𝒈(𝒂) 𝒍𝒐𝒈𝒄 (𝒂)
( )
For example: 𝑙𝑜𝑔 (3) = ( )
(Here we changed the base to 10)
Some solved problems:
Example 1. Convert the following exponential forms into logarithmic forms:
(i) 9 = 729 (ii) 7 = 16807 (iii) 2 = 1024
(iv) 10 = 0.001 (v) 4 = 0.0625 (vi) 5 = 0.0016
(vii) 10 = 1 (viii) 8 = 1
Ans. (i) Given that 9 = 729
⇒ 𝑙𝑜𝑔 729 = 3 (𝑏𝑦 𝑑𝑒𝑓𝑖𝑛𝑖𝑡𝑖𝑜𝑛)
which is required logarithmic form.
, OR
Given that 9 = 729
Taking logarithm on both sides, we get
𝑙𝑜𝑔9 = 𝑙𝑜𝑔729
⇒ 3 𝑙𝑜𝑔9 = 𝑙𝑜𝑔729 (𝑢𝑠𝑒𝑑 𝑝𝑜𝑤𝑒𝑟 𝑝𝑟𝑜𝑝𝑒𝑟𝑡𝑦 )
⇒ 3=
( )
⇒ 3 = 𝑙𝑜𝑔 729 𝑢𝑠𝑒𝑑 𝑙𝑜𝑔 𝑏 = ( )
which is required logarithmic form.
(ii) Given that 7 = 16807
⇒ 𝑙𝑜𝑔 16807 = 5 (𝑏𝑦 𝑑𝑒𝑓𝑖𝑛𝑖𝑡𝑖𝑜𝑛)
which is required logarithmic form.
OR
Given that 7 = 16807
Taking logarithm on both sides, we get
𝑙𝑜𝑔7 = 𝑙𝑜𝑔16807
⇒ 5 𝑙𝑜𝑔7 = 𝑙𝑜𝑔16807 (𝑢𝑠𝑒𝑑 𝑝𝑜𝑤𝑒𝑟 𝑝𝑟𝑜𝑝𝑒𝑟𝑡𝑦 )
⇒ 5=
( )
⇒ 5 = 𝑙𝑜𝑔 16807 𝑢𝑠𝑒𝑑 𝑙𝑜𝑔 𝑏 = ( )
which is required logarithmic form.
(iii) Given that 2 = 1024
⇒ 𝑙𝑜𝑔 1024 = 10
which is required logarithmic form.
(iv) Given that 10 = 0.001
⇒ 𝑙𝑜𝑔 0.001 = −3
which is required logarithmic form.
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