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Formulario quimica (soluciones y gases)

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En este documento encuentras las ecuaciones necesarias para lograr resolver ejercicios químicos, de forma concentrada, con una descripción de cada variable. De forma sencilla podrás resolver ejercicios de soluciones y gases químicos.

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  • April 19, 2023
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  • 2022/2023
  • Interview
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Concentration Dilucioñdesoluciones

Fisica
↳%
:( 1.100 Ms : Nsa C =
F- → CU =Ms

C IV CZVZ

{
=
Counter ion
Sokoto , ,
.




Ms = Masa
"

99 ✓
my =
masasolocioñ 2=4+4-120
my
,=m , ,
.




Czcv , -11-12037
.





① uimica IV ,
=
Ms =
mi tmtho




M=¥ ¥ ¥ ]
↳ Mercia de Soluciones
, ,
. . . .





Ns=mJ Zg=CV
MS




M-m7.ir#Zsl-Zss--Zsz
Ms # moles del sduto

GV, t CzUz = ( z V3
Usd = Volumes desolucion

Mg = Masa

V3 = V1 + V2
Ms = peso molecular


M molaridad
=




factor de Correa.in .





Normalidad
> la cntd mas
peqeeñ
-
con la se combiner Sokoto
que on


egg
.




#
µ '
vsot
Constante Criscopica

Equivalent ◦
peso equivalent e :




¥7
"


%;!j→
" -




aluneiementoei equivalent
peso atomic o ✗ Mmold £
@9 '

h
# Nclb
de Oxidation

↳Valencia estable /g
eat

calor talent .




b) Equivalent es de un a' cido :



12=1.987
fotacido :




Base Variaciodela Temperature
c) Equivalents de una
'm 1^9 ii. ¥7 Variacién temp
ebullition
→ peso Steb
.




=




£9 Base =
M

#oµ-
base
Ateb=FfjÉ%

ms

Is
= Masa del Sotto
Peso molecular
¥ ¥
--


% ,
↳ no oxidrilos g. constante criosccobica
kcg=
del disolutoenkg
kgd =
masa

d) fq.de una sustanciapredox
C-a- redox
=m¥%
kMn04-% K +
Mnoy Ecf -15-8=31 .bg
Presion Osmotic a
kmnoy =




81-1 + 111m04 _¥Mn -141-120 IT = C. R -7
Imo / konnoy Seq kmnoy

TF -5.316%-1589
=

IT =
presionosmoticafa -17
C = [ M]

C- £ 1<2407 2k TCROÉZ 12--0.082 FI
qkzcr 201 94g →

49g 7
'

= = = k
6
14 +
Cozy 2Gt 7-1-10

Tmo / kzGzOz=6eg kzcrzoz




e) fq .
Sal


Easa
'=¥É¥




Molalidad /M )

m
-7%-1*1 .


Ms
Ms -
-




ins

M=Ms_→masa
Sokoto
Mg -

kgd

Peso
Sokoto





Grados Belme




%§so1=¥µ
densos que
liquids
fsd-jyg.BE
mas
145
→ el
agua


→ liquid osmenosdeusos que
el


agua

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