The lengths of the sides of a triangle are 6, 8 and 12. If the length of the
shortest side of a similar triangle is 10, what is the length of its longest
side?
Solution:
P1 = 6 + 8 + 12
P1 = 26
6
8
P1 6
=
P2 10 12
26(10)
P2 =
6 6 y
P2 = 43.33
26 12 x
=
43.33 x
x = 20
, Refresher - MATHEMATICS Quiz 7
PROBLEM 2:
Given a complex numbers in Cis form 8 Cis 40˚ and 2 Cis – 40˚. Find the
value of (8 Cis 40˚)(2 Cis – 40˚).
Solution:
(8 Cis 40˚)(2 Cis – 40˚)
8(2) Cis [40˚ + (- 40˚)]
16 Cis 0˚
But Cis 0˚ = Cos 0˚ + i Sin 0
Cis 0˚ = 1
Therefore (8 Cis 40˚)(2 Cis – 40˚) = 16
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