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BTEC APPLIED SCIENCE UNIT 2 - Learning aim A

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A: Undertake titration and colorimetry to determine the concentration of solutions. Grade Distinction.

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Subido en
6 de junio de 2023
Número de páginas
8
Escrito en
2022/2023
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Emilia Hawkins


Unit 2: Practical Scientific Procedures and Techniques

A: Undertake titration and colorimetry to determine the concentration of solutions.



Titration

Calibrate equipment

Pipette Burette
Mass of beaker plus 25cm³ water 69.44 69.28
Mass of empty beaker 44.57 44.57
Mass of 25cm³ water 24.87 24.71


Preparation of standard solution Na₂CO₃

The sodium carbonate standard solution was made by measuring out approximately 1.3g of sodium
carbonate to a 250cm³ standard flask; making sure to reweigh the original beaker to get an accurate
mass. Then 100cm³ of distilled water was added to the flask, to dissolve the sodium carbonate, and
make sure that the solution reached the mark on the volumetric flask.

Concentration of standard solution:

250cm³ = 0.25dm³

Moles = mass/Mr

Moles = 1.3g/105.99 = 0.012 mol

Concentration = Moles/Volume

Concentration = 0.012/0.25 = 0.048 mol/dm³



Standardisation of given HCl by titration with primary standard solution Na ₂CO₃

After the standard solution had been prepared, I filled a burette with hydrochloric acid and
transferred 25cm³ of the sodium carbonate standard solution into a conical flask. A few drops of
indicator were then added to the conical flask and the HCl was titrated until the colour changed. I
repeated this process 3 times to increase the accuracy of my results.

Na₂CO₃ + 2HCl > NaCl + CO₂ + H₂O

Initial Volume/cm³ 00.00 00.00 00.00 00.00
Final Volume/cm³ 25.00 25.50 25.10 25.00
Titre/cm³ 25.00 25.50 25.10 25.00


Average = 25.033cm³ / 0.025033dm³

Volume = 5cm³/0.005cm³

Moles (Sodium carbonate) = Concentration (Sodium carbonate) x Volume (Sodium carbonate)

Moles = 0.048 x 0.005 = 0.00024

, Emilia Hawkins


Moles (Hydrochloric acid) = 2 x Moles (Sodium carbonate)

Moles = 2 x 0.00024 = 0.00048mol

Concentration (Hydrochloric acid) = Moles (Hydrochloric acid) / Volume (Hydrochloric acid)

Concentration = 0..025033 = 0.01917 mol/dm³



Titration of NaOH solution of unknown concentration with the standardized HCl

Titration using indicator

When titrating using an indicator, I first needed to calibrate the equipment and then measure 25cm³
of sodium hydroxide of unknown concentration into a 250cm³ conical flask. A few drops of indicator
were added to the conical flask; in this experiment I used phenolphthalein as an indicator. I then
filled a burette with hydrochloric acid and titrated this into the sodium hydroxide solution until the
colour changed. The values were recorded and I repeated the experiment 2 more times to increase
the accuracy of my results.

Titration using pH meter

When titrating using a pH meter, I needed to first calibrate the pipette I was using, and then transfer
25cm³ of sodium hydroxide solution into a small beaker. The pH meter was then calibrated using the
buffer solutions that was provided, and then it was placed into the beaker containing the sodium
hydroxide solution. I filled a burette with hydrochloric acid and this was added to the beaker in 1cm³
portions until the burette was empty. The pH levels were measured every time hydrochloric acid was
added and the results were recorded. I then plotted a graph of change in pH divided by change in
volume over volume HCl added and pH over volume added.



Results

Indicator

NaOH + HCl > NaCl + H₂O

Initial Volume/cm³ 00.00 00.00 00.00
Final Volume/cm³ 25.30 25.50 25.30
Titre/cm³ 25.30 25.50 25.30


Average = 25.367cm³ / 0.025367 dm³

Sodium hydroxide = 25cm³ , 0.1mol/dm³

Moles (Sodium hydroxide) = Concentration (Sodium hydroxide) x Volume (Sodium hydroxide)

Moles = 0.1 x 0.025 = 0.0025mol

Concentration (Hydrochloric acid) = Moles (Hydrochloric acid) / Volume (Hydrochloric acid)

Concentration = 0..025367 = 0.9855 mol/dm³
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