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BNU1501 EXAM PACK 2023
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BNU1501 EXAMPACK 2023
UPDATED REVISION
PACK 2023
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UNIVERSITY EXAMINATIONS
mm
mm
MAY/JUNE 2020
BNU1501
BASIC NUMERACY
Duration: 2 Hours 30 Minutes 100 Marks
EXAMINERS
FIRST DR MT MASETSHABA
SECOND MS BS NCUBE
EXTERNAL DR HARRY WIGGINS (University of Pretoria)
This paper consists of 10 pages, which include a list of formulas on page 10.
Programmable calculator permissible.
Instructions:
The paper consists of 25 questions for a total of 100 marks. Answer all the questions.
Only one option indicated as [1], [2], [3] or [4] per question is correct.
Marks will not be deducted for incorrect answers.
The answers to the examination MCQ may only be submitted online.
Submit the answers on my Unisa by
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my
paper: Login and download my Exam Question Paper for May/June 2020.
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display if the examination session is still open for submissions.
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CONFIDENTIAL BNU1501
Page 2 of 10 May/June 2020
Question 1
The expres
35 ÷ 5 + 2 − ((3 × 4 − 2) − (18 − 3 × 4))
can be rewr
[1] 9 − 6 + 42 .
[2] 9 − 10 + 6 .
[3] 5 − 6 + 42 .
[4] 5 − 10 + 6 .
Question 2
Subtracting 2x + x3 and x+7 from −8 − 5x3 + 4x gives
[1] −15 − 6x3 + x .
[2] 3x + x3 + 7 .
[3] −x + 6x3 + 15 .
[4] 7x − 4x3 + 15 .
Question 3
The option
√ √3
2 25 − 54 + 9 + 42
is
√ √3
[1] 23 2 − 3 2 + 5 .
√
[2] 23 − 3 2 + 5 .
√ √
[3] 8 2 − 33 2 × 3 + 3 + 4 .
√
[4] 5 2+7 .
Question 4
The expres
a3 × b5
b9 × a 5
is
1
a × b2
[1] .
[2] a−1 b−2 .
√
[3] ab2 .
−1
[4] ab2 .
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,
Distribution of this document is illegal
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280 minutes.
[4]
107 minutes.
[3]
131 minutes.
[2]
150 minutes.
[1]
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Question 7
. x = −2 [4]
. [3]
8
x=
11
. [2]
8
x=−
1
. [1]
5
x=−
1
gives
2
−1(x − 3) + 2x = −3x +
5
in the equation
x Solving for t
Question 6
. [4]
2
(x + 3)
1
. [3]
2
x+3+ x
1
. [2]
2
x+3
1
. [1]
2
x+3×
1
is
a number increased by 3 and then halved
The correct
Question 5
May/June 2020 Page 3 of 10
BNU1501 CONFIDENTIAL
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