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An aluminum link is subjected to axial tension.The loading is limit
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  • HBO Small Business en Ondernemerschap
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  • HBO Small Business En Ondernemerschap

An aluminum link is subjected to axial tension.The loading is limited by the conditions of not yielding and not elongating excessively. The yield limit is satisfied if the stress remains below 50% of the 325 MPa yield stress. The elongation must remain below 0.1 mm. The link cross-section is re...

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  • June 26, 2023
  • 1
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers

Subjects

  • aluminum link
  • link is
  • is subjected
  • subjected axial
  • loading is
  • is limit
  • axial tensionthe
  • tensionthe loading

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  • HBO Small Business en Ondernemerschap
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An aluminum link is subjected to axial tension.The loading is limited by the conditions
of not yielding and not elongating excessively. The yield limit is satisfied if the stress remains
below 50% of the 325 MPa yield stress. The elongation must remain below 0.1 mm. The link
cross-section is rectangular, 3 mm by 7 mm. Assuming elastic behavior, determine the maximum
allowable tensile force for two cases: (a) the length of the link is 35 mm and (b) the length of the
link is 55 mm.


Solution


Area of the cross section = 7*3*10^-6 = 21*10^-6 m^2
Maximum allowable stress = 325 Mpa
Allowable tensile load (T) = Stress * Area = 325*10^6 * 21*10^-6 = 6825 N



a) Young\'s modulous of alluminium is 69 Gpa
So, strain = 0.1/35 = 2.85 *10^-3
Stress = young\'s modulous * strain = 69*10^9 * 2.85*10^-3 = 197.14*10^6 = 197.14 MPa
Hence, stress is less than 325 Mpa, so the tensile load is limited by the maximum elongation
condtion.
Maximum allowed force = Stress * area = 197.14*10^6 * 21*10^-6 = 4139.9 N



b) Strain = (0.1/55) = 1.818 *10^-3
Stress = young\'s modulous * strain = 69*10^9 * 1.818*10^-3 = 197.14*10^6 = 125.44 MPa
Again stress is less than 325 Mpa, so the tensile load is limited by the maximum elongation
condtion.
Maximum allowed force = Stress * area = 125.44*10^6 * 21*10^-6 = 2634.28 N



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