AS Level Chemistry A H032/02 Depth In Chemistry Sa
AS Level Chemistry A H032/02 Depth in chemistry Sa
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AS Level Chemistry A H032/02 Depth in chemistry Sample Question Paper
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AS Level Chemistry A H032/02 Depth in chemistry Sa
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AS Level Chemistry A H032/02 Depth In Chemistry Sa
AS Level Chemistry A H032/02 Depth in chemistry Sample Question Paper
Date – Morning/Afternoon
Time allowed: 1 hour 30 minutes
* 0 0 0 0 0 0 *
INSTRUCTIONS
• Use black ink. HB pencil may be used for graphs and diagrams only.
• Complete the boxes above with your...
AS Level Chemistry A H032/02 Depth in chemistry Sa
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AS Level Chemistry A
H032/02 Depth in chemistry
Sample Question Paper
Date – Morning/Afternoon
Time allowed: 1 hour 30 minutes
Specim
You must have:
the Data Sheet for Chemistry A
You may use:
a scientific calculator
* 0 0 0 0 0 0 *
First name
Last name
Centre
en
Candidate
number number
INSTRUCTIONS
• Use black ink. HB pencil may be used for graphs and diagrams only.
• Complete the boxes above with your name, centre number and candidate number.
• Answer all the questions.
• Write your answer to each question in the space provided.
• Additional paper may be used if required but you must clearly show
your candidate number, centre number and question number(s).
• Do not write in the bar codes.
INFORMATION
• The total mark for this paper is 70.
• The marks for each question are shown in brackets [ ].
• Quality of extended responses will be assessed in questions marked with an asterisk
(*).
• This document consists of 20 pages.
1 Bromine is a reactive element. It combines with other non-metals to form covalent compounds.
Phosphorus tribromide, PBr3, and iodine monobromide, IBr, are examples of covalent compounds used in
organic synthesis.
(a) PBr3 can be prepared by heating bromine with phosphorus, P4.
(i) Write an equation for this reaction.
…………………………………………………………………………………………. [1]
(ii) How many molecules are present in 1.3535 g of PBr3?
Specim
en number of molecules = ………………………
(iii) The ‘dot-and-cross’ diagram of a molecule of PBr3 is given below.
[3]
Name the shape of this molecule and explain why the molecule has this shape.
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