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CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam (Latest-2023): Portage Learning |100% Verified and Correct Q & A| $30.49
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CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam (Latest-2023): Portage Learning |100% Verified and Correct Q & A|
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  • Portage Learning

CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4 Exam, CHEM 103 Module 5 Exam, CHEM 103 Module 6 Exam (Latest-2023): Portage Learning |100% Verified and Correct Q & A| CHEM 103 Module 1 Exam, CHEM 103 Module 2 Exam, CHEM 103 Module 3 Exam, CHEM 103 Module 4...

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  • June 30, 2023
  • 42
  • 2022/2023
  • Exam (elaborations)
  • Questions & answers

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  • chem 103 module 1 exam
  • chem 103 module 2 exam
  • ch

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  • Portage Learning
  • CHEM 103: General Chemistry I w/Lab
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CHEM 103 Module 1, 2, 3, 4, 5, 6 Exam and CHEM 103 Final Exam

EXAM 1
Question 1


1. Convert 1005.3 to exponential form and explain your answer.




2. Convert 4.87 x 10-6 to ordinary form and explain your answer.



Answer:

1. Convert 1005.3 = larger than 1 = positive exponent, move decimal 3 places = 1.0053
x 103



2. Convert 4.87 x 10-6 =negative exponent =smaller than 1, move decimal 6 places =
0.00000487

Question 2


Using the following information, do the conversions shown below, showing all work:




1 ft = 12 inches 1 pound = 16 oz 1 gallon = 4 quarts




1 mile = 5280 feet 1 ton = 2000 pounds 1 quart = 2 pints




kilo (= 1000) milli (= 1/1000) centi (= 1/100)

,deci (= 1/10)




1. 2.73 liters = ? ml 2. 8.6 pts = ? qts




Answer:



1. 2.73 liters x 1000 ml / 1 liter = 2730 ml



2. 8.6 pts x 1 qt / 2 pts = 4.3 qts



Question 3


Do the conversions shown below, showing all work:




1. 248oC = ? oK




2. 25oF = ? oC




3. 175oK = ? oF




Answer:



1. 248oC + 273 = 521 oK oC → oK (make larger) +273

,2. 25oF - 32 ÷ 1.8 = -3.88 oC oF → oC (make smaller) -32
÷1.8

3. 175oK - 273 = -98 oC x 1.8 + 32 = -144.4 oF oK → oC → oF



Question 4


Be sure to show the correct number of significant figures in each calculation.




1. Show the calculation of the mass of a 17.9 ml sample of chloroform with density
of 1.49 g/ml




2. Show the calculation of the volume of 19.4 grams of cresol with density of 1.02
g/ml


Answer:
1. M = D x V = 1.49 x 17.9 = 26.7 g



2. V = M / D = 19..02 = 19.0 ml
Question 5


1. 1.35601 contains ? significant figures.




2. 0.151 contains ? significant figures.




3. 1.35601 + 0.151 = ? (give answer to correct number of significant figures)



Answer:

, 1. 1.35601 contains 6 significant figures.

2. 0.151 contains 3 significant figures.

3. 1.35601 + 0.151 = 1.50701 = 1.507 (to the thousands place for 0.151)


Question 6


Classify each of the following as an element, compound, solution or heterogeneous
mixture and explain your answer.




1. Honey




2. Hydrogen iodide




3. Tea




Answer:

1. Honey - is not on periodic table (not element) - no element names (not
compound) appears to be one substance = Solution

2. Hydrogen iodide - is not on periodic table (not element) - has two element names
= Compound

3. Tea - is not on periodic table (not element) - no element names (not compound)

appears to be one substance = Solution

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