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Mole Concept PART 2 | NEET Conquer Batch 2024 | Wassim Bhat Unacademy NEET
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Mole Concept PART 2 | NEETConquer Batch 2024 | Wassim
Bhat
- Unacademy NEET
Introduction
Welcome back to another session from the NEET
conquer batch with me, your chemistry educator
Wasimbat. In today's session, we will be
discussing the second part of the Mole Concept
chapter, where we will be covering the mass
method of stoichiometry. Let's get started!
Overview
We have already completed about 50-60% of the
chapter in the previous session, where we
covered stoichiometry using the mole method.
Today, we will be covering the remaining part of
the Mole Concept chapter. The session will be
about 4 hours long, and there will be no breaks in
between.
Mass Method
When using either the mole method or the mass
method in stoichiometry, the first step is always
to balance the reaction equation.
,After balancing the equation, the given quantity
must be converted into mass for the mass
method. In our example question, we have to
calculate the mass of oxygen gas produced on
heating 12.25 grams of KClO3 at STP.
Example Question
Calculate the mass of oxygen gas produced on
heating 12.25 grams of KClO3 at STP.
Solution Using Mass Method
• Balance the reaction equation.
KClO3 → KCl + O2
2KClO3 → 2KCl + 3O2
• Convert the given quantity into mass.
We are given 12.25 grams of KClO3.
• Relate the given data to the data to be
calculated.
We need to calculate the mass of O2 produced.
So, we can relate the given quantity of KClO3 to
the mass of O2 produced.
245 grams of KClO3 upon heating gives 96 grams
of O2.
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