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MAT3702 Assignment TWO 2023

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UNISA Abstract Algebra MAT3702 Assignment TWO of 2023 solutions.

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  • July 3, 2023
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MAT3702 ASSIGNMENT TWO 2023

Question 1

𝑎𝑝−1 ≡ 24 (𝑚𝑜𝑑 5)

𝑎𝑝−1 ≡ 16 (𝑚𝑜𝑑 5)

15 = 5 × 3

16 − 1 = 5 × 3

5 divides (16 − 1)

Therefore,

𝑎𝑝−1 ≡ 1 (𝑚𝑜𝑑 5)



Question 2

𝑆 = {0, 3} is not a subring of ℤ6 because 𝑆 does not contain 1.

Question 3

𝑅 is a ring and 𝑏 ∈ 𝑅 such that 𝑏𝑏 = 𝑏.

Given that 𝑏 ≠ 0𝑅

Therefore, 𝑏 has a unique inverse 𝑏 −1 ∈ 𝑅 such that 𝑏𝑏 −1 = 1𝑅 = 𝑏 −1 𝑏

𝑏𝑏 = 𝑏

⇒ (𝑏𝑏)𝑏 −1 = 𝑏𝑏 −1

Rings are associative, therefore:

𝑏(𝑏𝑏 −1 ) = 𝑏𝑏 −1

𝑏1𝑅 = 1𝑅

𝑏 = 1𝑅

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