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Antwoorden Wiskunde B (Moderne wiskunde 11 editie) 4 VWO Hoofdstuk 7 $3.32
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Antwoorden Wiskunde B (Moderne wiskunde 11 editie) 4 VWO Hoofdstuk 7

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Antwoorden Moderne Wiskunde 11e editie Wiskunde B VWO Hoofdstuk 7

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  • March 13, 2017
  • 13
  • 2015/2016
  • Answers
  • Unknown
  • Secondary school
  • 4

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13 maart 2017




Hoofdstuk 7: Periodieke functies

V-1. AD  62  ( 20)2  4 en BC  72  ( 20)2  69

V-2. cos Q  8
9 tan D  17
1,5
sin 65o  MN
15
cos 65o  SN
15

Q  27o D  70o MN  13,59 SN  6,34
PR  9  8  17 2 2



V-3.
a. Ongeveer 18°C.
b. Het bereik: verschil tussen de hoogste en laagste temperatuur.
c. De gemiddelde jaartemperatuur is ongeveer 10°C.
d. ongeveer 14°C.

V-4.
a. maximum is 4,6 en het minimum -3,9
De evenwichtsstand: 0,34 en de amplitude: 4,25
De periode (van minimum tot minimum) is ongeveer 13 uur.
b. Alleen de evenwichtsstand daalt met 75 cm. Amplitude en periode blijven gelijk.
c. Vermenigvuldigen met 1,2
d. De periode en de evenwichtsstand blijven gelijk. De amplitude wordt 5,1




1.
a. Omtrek  2  1  2 meter.
b. 2 seconden.
c. De stip zit dan helemaal links.
d. Na een kwart omwenteling: 41  2  21   1,57 seconden.

2.
a. Helemaal rond is 360o . De stip heeft dan een afstand afgelegd van 2 .
Als de afstand  is, dan is de hoek 21  360o  180o
b. Werk met een verhoudingstabel:
x   :   180o  (rad )  180o
x  41  :   41  180o  45o
c. 5
12
 5
24
 2 , dus ook 5
24
 360o  75o
d. x  1:   180
  57,30o
1
Uitwerkingen 4 vwo wiskunde B, hoofdstuk 7

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