100% satisfaction guarantee Immediately available after payment Both online and in PDF No strings attached
logo-home
Summary Grade 12 IEB Physical Science: Momentum, Impulse, Work, Energy and Power $4.55   Add to cart

Summary

Summary Grade 12 IEB Physical Science: Momentum, Impulse, Work, Energy and Power

1 review
 24 views  0 purchase
  • Course
  • Institution
  • Book

These notes cover Section C as per the IEB Physical Science SAGS. Included are comprehensive notes and annotated examples on Linear Momentum (1D), Newton's Second Law expressed in terms of Momentum, Conservation of Momentum and Elastic and Inelastic Collisions, Impulse and Work, Energy and Power. A...

[Show more]
Last document update: 1 year ago

Preview 3 out of 22  pages

  • No
  • Momentum, impulse, work, energy and power
  • July 11, 2023
  • July 18, 2023
  • 22
  • 2022/2023
  • Summary
  • 200

1  review

review-writer-avatar

By: emmakalis • 3 months ago

avatar-seller
MOMENTUM, IMPULSE, WORK,
ENERGY AND POWER




@STUDYNOTESBYM

, C. MOMENTUM, IMPULSE, WORK, ENERGY AND POWER



1. LINEAR MOMENTUM (1D)

Linear momentum is the product of the mass and velocity of the object



p=mv
p: momentum measured in 𝑘𝑔. 𝑚. 𝑠 −1

m: mass measured in 𝑘𝑔

v: velocity measured in 𝑚. 𝑠 −1



• Momentum is a vector quantity (has a magnitude and direction) and is in the same
direction as the velocity
e.g.) if velocity is acting right, momentum will also act right


CALCULATING LINEAR MOMENTUM:
Example: A 500kg car drives along a city street at 13.4m/s. What is the car’s momentum?
Let forward be positive
1. Assign a positive
𝑝 = 𝑚𝑣 direction
= (500)(13.4) 2. Use the formula to
= 6700𝑘𝑔. 𝑚. 𝑠 −1 𝑓𝑜𝑟𝑤𝑎𝑟𝑑 calculate the
magnitude of the
momentum
3. State a direction

, 2. NEWTON’S SECOND LAW EXPRESSED IN TERMS OF MOMENTUM
(THE CHANGE IN MOMENTUM - ∆𝑃 )

The net force acting on an object is equal to the rate of change of momentum




∆𝒑
𝑭𝒓𝒆𝒔 =
∆𝒕
When an object experiences a resultant force, it will accelerate. Because it
accelerates, the velocity changes therefore the momentum of the object will
change:

∆𝒑 = 𝒎(𝑽𝒇 − 𝑽𝒊)
Therefore:


𝒎(𝑽𝒇 − 𝑽𝒊)
𝑭𝒓𝒆𝒔 =
∆𝒕


Example:
A 500g ball, travelling at 14m/s, is kicked. The ball moves off in the opposite direction at a speed
of 18m/s. If the ball was in contact with the kicker’s foot for 0.05s, calculate the resultant force
exerted on the ball
∆𝑝
𝐹𝑟𝑒𝑠 =
∆𝑡


𝑚(𝑉𝑓 − 𝑉𝑖 )
=
∆𝑡
0,5(−18 − 14)
=
0,05
= −320
= 320𝑁 𝑖𝑛 𝑡ℎ𝑒 𝑑𝑖𝑟𝑒𝑐𝑡𝑖𝑜𝑛 𝑜𝑓 𝑡ℎ𝑒 𝑘𝑖𝑐𝑘𝑒𝑟 ′ 𝑠 𝑓𝑜𝑜𝑡

The benefits of buying summaries with Stuvia:

Guaranteed quality through customer reviews

Guaranteed quality through customer reviews

Stuvia customers have reviewed more than 700,000 summaries. This how you know that you are buying the best documents.

Quick and easy check-out

Quick and easy check-out

You can quickly pay through credit card or Stuvia-credit for the summaries. There is no membership needed.

Focus on what matters

Focus on what matters

Your fellow students write the study notes themselves, which is why the documents are always reliable and up-to-date. This ensures you quickly get to the core!

Frequently asked questions

What do I get when I buy this document?

You get a PDF, available immediately after your purchase. The purchased document is accessible anytime, anywhere and indefinitely through your profile.

Satisfaction guarantee: how does it work?

Our satisfaction guarantee ensures that you always find a study document that suits you well. You fill out a form, and our customer service team takes care of the rest.

Who am I buying these notes from?

Stuvia is a marketplace, so you are not buying this document from us, but from seller studynotesbym. Stuvia facilitates payment to the seller.

Will I be stuck with a subscription?

No, you only buy these notes for $4.55. You're not tied to anything after your purchase.

Can Stuvia be trusted?

4.6 stars on Google & Trustpilot (+1000 reviews)

64438 documents were sold in the last 30 days

Founded in 2010, the go-to place to buy study notes for 14 years now

Start selling
$4.55
  • (1)
  Add to cart