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This document contains solutions for assignment 4, MAT1503
Typed not handwritten.
The solutions are 100% correct
To find values of k such that a33 = a233, we set them equal:
k + 14 = k + 9
5=0
Since there is no value of k that satisfies the equation, there are no values of k in the range
[-1, 0] that make a33 = a233.
(1.2) Performing the operation (3):
R1 ←→ R3
E2 =
[0 0 1]
[0 1 0]
[1 0 0]
Performing E2A:
C = E2A =
[1 -3 k + 14]
[3 1 -1]
[2 -1 1]
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