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Boletín de problemas electrónica

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  • August 19, 2023
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Boletín de problemas 2 Tema 5
Circuitos activos. Fuentes dependientes


NOTA: Los coeficientes de las ecuaciones resultantes de la apli-
cación de los métodos de nudos y mallas, se expresan mediante
números enteros primos entre sí. Sólo de esta manera se puntua-
rán como correctos.

1. En el circuito de la figura, calcula la ganancia de tensión:




VL VL
GV = =2 GV = =4
VS1 VS1
µ = 9, R1 = 25 Ω, R2 = 50 Ω, r = 1800 Ω, R1 = 100 Ω, R2 = 50 Ω,
R3 = 5 Ω, R4 = 10 Ω R3 = 20 Ω, R4 = 10 Ω

2. (1p) En el circuito de la figura, calcula la ganancia de tensión:




VL VL
GV = = −30 GV = = −8
VS1 VS1
g = 3 f, R1 = 50 Ω, R2 = 25 Ω, β = 150, R1 = 25 Ω, R2 = 50 Ω,
R3 = 30 Ω, R4 = 30 Ω R3 = 12 Ω, R4 = 6 Ω



1

, 3. En el circuito de la figura, se pide:




a.- La matriz de mallas a.- La matriz de nudos
         
20 −10 I1 1 1 0 0 VA 5
=  −2 5 −1 VB  = 0
16 1 I2 0
−50 50 1 VC 0
b.- La tensión VX = 277, 78 mV b.- La tensión VX = 272, 72 mV
VS1 = 5 V, µ = 25, R1 = 50 Ω, VS1 = 5 V, µ = 50, R1 = 25 Ω,
R2 = 50 Ω, R3 = 25 Ω R2 = 25 Ω, R3 = 50 Ω

4. En el circuito de la figura, se pide:




a.- La matriz de mallas a.- La matriz de nudos
         
10 −5 I1 1 1 0 0 VA 5
=  −1 4 −2 VB  = 0
49 3 I2 0
−25 25 1 VC 0
b.- La corriente IX = 10, 9 mA b.- La corriente IX = 5, 55 mA
VS1 = 5 V, r = 1250 Ω, R1 = 25 Ω, VS1 = 5 V, r = 1250 Ω, R1 = 50 Ω,
R2 = 25 Ω, R3 = 50 Ω R2 = 50 Ω, R3 = 25 Ω




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