Se cumplen las propiedades signientes:
(a) K" el coninto vacio son conjuntos algebraicos afines.
y p(X
Afirmo que VIo=R2.
"
Vamos a probarlo
""Trivial por definition (VISI k") =
"Sea atk" =
pla) 0= = atV(o)
Afirmo que VIKEX...., xn]) 0. Vamos =
a probarlo
P.R.A. VIK [Xn,..., xn])+0, dear atV/k2x.,..., xn)).
supongamos que es exist
Esto implicaria que plat 0,
=
Xp(MEKTXn,...,Xn]
Pero, existe q(=1EKIX...., xn] y q(a)=1 to, facK" por
# haber
que
supuesto
-
polinomio cte. 1 V (kEXn, ...,Xn]) 4 +
Concluimos que VIKTX, ...,
Xn]) 0=
(b) Si S, S'=
RIA...., n) S =S', entences VIS' VIS) =
y
Definimos VIS)=1 atk"/p(a) 0
=
, p(eS)
VIS" =
3beK"/q(b) 0,Xq(AcS) =
:VIS' VISI? =
SeS
Sea beVIS' =D q(b) 0,
=
Xq(At S
W
-q(b) 0,rq(tS D
-
=
= beV(S)
, (C) Si SEREX,..., xn] y
<S> es el ideal
generado por S, entences
V(S) v(<S) =
Definimos <S =(rst...+ raSn/SieS, riEKExn,..., Xn], neNY
VISI (
=
ack" / p(a) 0,
=
xp(xeS)
(bek"/q(b) 0,Xq(n<Sx)
V(<Sx) =
=
V(S1 =v(<S)
"-"
V(S)
S
=<S(V(< s)
=
"c"
aeVIS) = D pla) 0, XpIneS=<S
=
Sea q(x-<Sc D
=
q(M ri
=
+...+
ES rnInS q(a) rilalal?...+rnials, FaeUlS)
=
=> atV(S)
Como consecuencia, ECK" es un
conjunto algebraico atin si, y
solo si, E=V(I), donde I es un ideal dil avillo de
policomics
kIA...., Xn] y se complex has
propiedades:
(d) Si Inletes una familia arbitraria de ideates de KIxn,..., n3,
entonces:
SV(In) V(Y 22) V(2n)
= =
Y por to tanto, la intersection arbitraria de
conjuntos algebraicos
afines, as tambien un atin.
conjunto
⑮
-
3 V122) V)kIel? =
Sea (VIIa
at =D
pulal 0,
=
Xprklehn, XR x
=
p(a) 0,
=
XpIeYIr = aEVIV,In
·VIWIn) VIE Ie)? =
Saberos que E12 x, Zn
=
=
VIE,de) VkEdn"V(WInl
=
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